son*_*rin 12 gradle querydsl spring-boot
我希望通过gradle将querydsl带入我的spring-boot项目.尽管在网上找到了几个例子,但由于依赖性问题(我认为),它们实际上都不适合我.根据QueryDSL支持论坛,尚不支持gradle.但是我想知道如果有人设法让它工作了所有的gradle和spring-boot?
这是我的build.gradle:
apply plugin: 'java'
apply plugin: 'groovy'
apply plugin: 'idea'
apply plugin: 'spring-boot'
apply plugin: 'jacoco'
apply plugin: 'war'
buildscript {
repositories {
maven { url "http://repo.spring.io/libs-snapshot" }
mavenLocal()
}
dependencies {
classpath("org.springframework.boot:spring-boot-gradle-plugin:1.0.0.RC4")
}
}
repositories {
mavenCentral()
maven { url: "http://repo.spring.io/libs-snapshot" }
// maven { url: "http://repo.spring.io/milestone" }
}
dependencies {
compile("org.springframework.boot:spring-boot-starter-web:1.0.0.RC5")
compile("org.springframework.boot:spring-boot-starter-data-jpa:1.0.0.RC5")
compile("org.springframework:spring-orm:4.0.0.RC1")
compile("org.hibernate:hibernate-entitymanager:4.2.1.Final")
compile("com.h2database:h2:1.3.172")
compile("joda-time:joda-time:2.3")
compile("org.thymeleaf:thymeleaf-spring4")
compile("org.codehaus.groovy.modules.http-builder:http-builder:0.7.1")
compile('org.codehaus.groovy:groovy-all:2.2.1')
compile('org.jadira.usertype:usertype.jodatime:2.0.1')
// this line fails
querydslapt "com.mysema.querydsl:querydsl-apt:3.3.2"
testCompile('org.spockframework:spock-core:0.7-groovy-2.0') {
exclude group: 'org.codehaus.groovy', module: 'groovy-all'
}
testCompile('org.codehaus.groovy.modules.http-builder:http-builder:0.7+')
testCompile("junit:junit")
}
jacocoTestReport {
group = "Reporting"
description = "Generate Jacoco coverage reports after running tests."
}
task wrapper(type: Wrapper) {
gradleVersion = '1.11'
}
sourceSets {
main {
generated {
java {
srcDirs = ['src/main/generated']
}
}
java {
srcDirs = []
}
groovy {
srcDirs = ['src/main/groovy', 'src/main/java']
}
resources {
srcDirs = ['src/main/resources']
}
output.resourcesDir = "build/classes/main"
}
test {
java {
srcDirs = []
}
groovy {
srcDirs = ['src/test/groovy', 'src/test/java']
}
resources {
srcDirs = ['src/test/resources']
}
output.resourcesDir = "build/classes/test"
}
}
configurations {
// not really sure what this is, I see it in examples but not in documentation
querydslapt
}
task generateQueryDSL(type: JavaCompile, group: 'build', description: 'Generates the QueryDSL query types') {
source = sourceSets.main.java
classpath = configurations.compile + configurations.querydslapt
options.compilerArgs = [
"-proc:only",
"-processor", "com.mysema.query.apt.jpa.JPAAnnotationProcessor"
]
destinationDir = sourceSets.generated.java.srcDirs.iterator().next()
}
compileJava {
dependsOn generateQueryDSL
source generateQueryDSL.destinationDir
}
compileGeneratedJava {
dependsOn generateQueryDSL
options.warnings = false
classpath += sourceSets.main.runtimeClasspath
}
clean {
delete sourceSets.generated.java.srcDirs
}
idea {
module {
sourceDirs += file('src/main/generated')
}
}
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但gradle失败了:
Could not find method querydslapt() for arguments [com.mysema.querydsl:querydsl-apt:3.3.2]
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我已经尝试将querydsl-apt版本更改为早期版本,但我得到了同样的错误.
Spring Boot 1.3.5的工作配置和支持的QueryDSL,使用gradle 2.14进行测试.
ext {
queryDslVersion = '3.6.3'
javaGeneratedSources = file("$buildDir/generated-sources/java")
}
compileJava {
doFirst {
javaGeneratedSources.mkdirs()
}
options.compilerArgs += [
'-parameters', '-s', javaGeneratedSources
]
}
dependencies {
compile('org.springframework.boot:spring-boot-starter-data-jpa')
compile "com.mysema.querydsl:querydsl-jpa:$queryDslVersion"
compileOnly "com.mysema.querydsl:querydsl-apt:$queryDslVersion:jpa"
}
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完整的项目源代码:spring-boot-querydsl
您可能至少需要做两件事:
在使用之前声明“querydslapt”配置
将 querydsl-jpa (或任何您需要的风格)添加到您的“编译”配置中。
然后您将设置类路径,但如果没有更多配置,apt 位将不会执行任何操作(正如您从 querydsl 支持论坛中毫无疑问地发现的那样)。apt but 用于生成一些代码,然后您需要在应用程序代码中编译和使用这些代码(与您的域对象对应的“Q*”类)。我想你可以从 gradle 中的构建任务中驱动它(它只需要为域对象中的每个更改运行一次)。
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