无法分配django.utils.functional.SimpleLazyObject,必须是用户实例

Question

在视图中将django.contrib.auth.models中的User对象分配给具有对User的外键引用的模型对象的正确方法是什么？示例中的new_contact:

def index(request):
    form = SignupForm(request.POST or None)
    if form.is_valid():
        new_contact = form.save(commit=False)
        new_contact.user = request.user
        new_contact.save()
        # send_mail ...
        return HttpResponseRedirect(reverse('app:template'))
    else:
        return render_to_response('index.html', {'form': form}, context_instance=RequestContext(request))

"new_contact.user = request.user"抛出错误ValueError at/Can not assign"":"Contact.user"必须是"User"实例,因为request.user是一个对象包装器,而不是实际的User(不存在)然而).但是如果我设置new_contact.user = auth.get_user(request)[基于这里的答案:modelforms中的valueError ],它会返回NameError'autah',即使我将django.contrib.auth导入到我的视图中.这样做的正确方法是什么？谢谢

我的模型是:

from django import forms
from .models import Contact

class SignupForm(forms.ModelForm):
 class Meta:
    model = Contact
    fields = ['name','email','company']

Answer 1

import语句应该是:

from django.contrib.auth import get_user

并实际呼吁get_user():

new_contact.user = get_user(request)

仅供参考,django.contrib.auth 来源:

def get_user(request):
    """
    Returns the user model instance associated with the given request session.
    If no user is retrieved an instance of `AnonymousUser` is returned.
    """
    ...

希望有所帮助.