ORA-12505,TNS:监听器当前不知道连接描述符中给出的SID.Eclipse和Fedora 20通过JDBC

Question

我在Fedora 20虚拟机上安装了Oracle 11g XE,配置它并设置环境变量(运行oracle_env.sh).尝试使用此字符串通过jdbc将Eclipse与数据库连接时,我遇到此错误 "jdbc.databaseurl=jdbc:oracle:thin:@192.168.88.134:1521:XE"

我可以通过SQL*Plus(sqlplus / as sysdba)连接到虚拟机中的数据库.

的$ORACLE_SID变量是确定(XE).我已经尝试停止并启动监听器,然后启动数据库,并使用该alter system register;命令.

还静态注册数据库没有成功(我不能确定我没有误解这样做,所以如果有人认为这可以解决我的问题,我会再试一次).

这是listener.ora文件:

# listener.ora Network Configuration File: 

SID_LIST_LISTENER = 
  (SID_LIST = 
    (SID_DESC = 
      (SID_NAME = PLSExtProc) 
      (ORACLE_HOME = /u01/app/oracle/product/11.2.0/xe) 
      (PROGRAM = extproc) 
    ) 
  ) 



LISTENER = 
  (DESCRIPTION_LIST = 
    (DESCRIPTION = 
      (ADDRESS = (PROTOCOL = IPC)(KEY = EXTPROC_FOR_XE)) 
          (ADDRESS = (PROTOCOL = TCP)(HOST = 192.168.88.134)(PORT = 1521)) 
    ) 
  ) 

DEFAULT_SERVICE_LISTENER = (XE) 

和tnsnames.ora文件:

# tnsnames.ora Network Configuration File: 

XE = 
  (DESCRIPTION = 
    (ADDRESS = (PROTOCOL = TCP)(HOST = 192.168.88.134)(PORT = 1521)) 
    (CONNECT_DATA = 
      (SERVER = DEDICATED) 
      (SERVICE_NAME = XE) 
    ) 
  ) 

EXTPROC_CONNECTION_DATA = 
  (DESCRIPTION = 
    (ADDRESS_LIST = 
      (ADDRESS = (PROTOCOL = IPC)(KEY = EXTPROC_FOR_XE)) 
    ) 
    (CONNECT_DATA = 
      (SID = PLSExtProc) 
      (PRESENTATION = RO) 
    ) 
  ) 

而且lsnrctl status:

LSNRCTL for Linux: Version 11.2.0.2.0 - Production on 31-MAR-2014 01:22:35 

Copyright (c) 1991, 2011, Oracle.  All rights reserved. 

Connecting to (DESCRIPTION=(ADDRESS=(PROTOCOL=IPC)(KEY=EXTPROC_FOR_XE))) 
STATUS of the LISTENER 
------------------------ 
Alias                     LISTENER 
Version                   TNSLSNR for Linux: Version 11.2.0.2.0 - Production 
Start Date                30-MAR-2014 22:41:35 
Uptime                    0 days 2 hr. 41 min. 1 sec 
Trace Level               off 
Security                  ON: Local OS Authentication 
SNMP                      OFF 
Default Service           XE 
Listener Parameter File   /u01/app/oracle/product/11.2.0/xe/network/admin/listener.ora 
Listener Log File         /u01/app/oracle/product/11.2.0/xe/log/diag/tnslsnr/192/listener/alert/log.xml 
Listening Endpoints Summary... 
  (DESCRIPTION=(ADDRESS=(PROTOCOL=ipc)(KEY=EXTPROC_FOR_XE))) 
  (DESCRIPTION=(ADDRESS=(PROTOCOL=tcp)(HOST=192.168.88.134)(PORT=1521))) 
Services Summary... 
Service "PLSExtProc" has 1 instance(s). 
  Instance "PLSExtProc", status UNKNOWN, has 1 handler(s) for this service... 
The command completed successfully

我几乎可以肯定问题是监听器不知道数据库.除了它已经显示的内容之外,上一个命令应该显示类似的内容

Service XE has 1 instance.
Instance "XE", status READY, has 1 handler for this service

......但它没有,我不知道如何解决这个问题.

我是新手,主要是在Linux上,所以我将欣赏你建议的解决方案中的每一个细节.

Answer 1

这听起来像您的数据库尝试使用错误的IP地址注册以联系侦听器.您的侦听器配置为侦听192.168.88.134,但可能DB正在假设localhost(127.0.0.1),或者如果配置已更改,则为旧IP值.

默认情况下,数据库将尝试针对服务器的外部主机名注册(默认情况下local_listener为空),但您可能会从中获取意外值 - 因此/etc/hosts,机器名称的重要性.无论是什么导致了这种情况,注册似乎都失败了.

您可以使用实际的侦听器地址明确告诉DB注册:

alter system set local_listener = '192.168.88.134:1521' scope=memory;
alter system register;

如果这样做并且lsnrctl services现在显示XE,则重复该set命令scope=both以使其坚持下一次重新启动数据库.