Android ShowCaseView的buttonLayoutParams不起作用

Question

我在我的应用程序中使用ShowCaseView库.我想将"确定"按钮移到左侧.我使用了这段代码(在库中也一样):

// The following code will reposition the OK button to the left.
RelativeLayout.LayoutParams lps = new RelativeLayout.LayoutParams(
            ViewGroup.LayoutParams.WRAP_CONTENT,
            ViewGroup.LayoutParams.WRAP_CONTENT);
lps.addRule(RelativeLayout.ALIGN_PARENT_BOTTOM);
lps.addRule(RelativeLayout.ALIGN_PARENT_LEFT);
int margin = ((Number) (getResources().getDisplayMetrics().density * 12))
        .intValue();
lps.setMargins(margin, margin, margin, margin);
View showcasedView = findViewById(R.id.ib_next);
ViewTarget target = new ViewTarget(showcasedView);
ShowcaseView.ConfigOptions co = new ShowcaseView.ConfigOptions();
co.buttonLayoutParams = lps;
co.fadeInDuration = 1000;
co.fadeOutDuration = 1000;
ShowcaseView sv = ShowcaseView.insertShowcaseView(target, this,
        R.string.showcase_title, R.string.showcase_details, co);

但它不起作用？任何人都可以告诉问题在哪里？

Answer 1

我知道这个问题已经过时了,但万一有人需要一个有效的解决方案:

RelativeLayout.LayoutParams lps = new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT);
// This aligns button to the bottom left side of screen
lps.addRule(RelativeLayout.ALIGN_PARENT_BOTTOM);
lps.addRule(RelativeLayout.ALIGN_PARENT_LEFT);
// Set margins to the button, we add 16dp margins here
int margin = ((Number) (getResources().getDisplayMetrics().density * 16)).intValue();
lps.setMargins(margin, margin, margin, margin);

ViewTarget target = new ViewTarget(R.id.buttonBlocked, this);
sv = new ShowcaseView.Builder(this)
        .withMaterialShowcase()
        .setTarget(target)
        .setContentTitle(R.string.showcase_main_title)
        .setContentText(R.string.showcase_main_message)
        .build();
// Set declared button position to ShowcaseView
sv.setButtonPosition(lps);

这对我有用,希望对某人有所帮助.