我腌制了我的元组

Question

我还是python的新手.我正在为更大的项目工作框架.这个程序让你想到一个圆圈或正方形,然后它会问四个问题,然后决定一个答案.

我正处于框架的最后一步,但遇到了问题.我得到"全局名称'qas1'未定义"

getQuestion中的第50行问题='qas'未定义全局名称'qas'

当我试图腌制我的元组时,就会发生这种情况.

这是我的加载程序,用于创建包含我的元组的pickle文件:

import cPickle
import os

qas1 = [
('Are you more like Waffle or a Pancake'), 
('1. Waffle', 1, 0),
('2. Pancake', 0, 1)
]

qas2 = [
('Do you have a straight edge?'),
('1. Yes', 1, 0),
('2. No', 0, 1)
]

qas3 = [
('Are you simliar in shape to a lolipop?'),
('1. Yes', 0, 1),
('2. No', 1, 0)
]
qas4 = [
('Is the world rounded like a planet, or flat like a map?'),
('1. Rounded', 0, 1),
("2. Flat", 1, 0)
]

def hasFile():
    print 'I see the file'
    qas_file = open('qas.dat', 'r')
    qas1 = cPickle.load(qas_file)
    qas2 = cPickle.load(qas_file)
    qas3 = cPickle.load(qas_file)
    qas4 = cPickle.load(qas_file)
    qas_file.close
    confirmer()

def noFile():
    print 'I dont see a file...'
    saver()

def confirmer():
    print qas1
    print qas2
    print qas3
    print qas4

def saver():
    qas_file = open('qas.dat', 'w')
    print 'No worries, creating one now'
    cPickle.dump(qas1, qas_file)
    cPickle.dump(qas2, qas_file)
    cPickle.dump(qas3, qas_file)
    cPickle.dump(qas4, qas_file)
    qas_file.close
    print 'all done'

fname = "qas.dat"
if os.path.isfile(fname):
    hasFile()
else:
    noFile()

代码工作正常,但是当我尝试使用它创建的文件时遇到了问题.

import cPickle

#Counters
counterCircle = 0
counterSquare = 0

# tuples
def hasFile():
    print 'I see the file'
    qas_file = open('qas.dat', 'r')
    qas1 = cPickle.load(qas_file)
    qas2 = cPickle.load(qas_file)
    qas3 = cPickle.load(qas_file)
    qas4 = cPickle.load(qas_file)
    qas_file.close



#varibles Im made to assign
messageDisplayed = 0
question = 'beer'

#prints to screen   
def showQaA():
    print question[0]
    print question[1][0]
    print question[2][0]

#recieves and implements responses
def getResponce():
    global counterCircle
    global counterSquare
    global qas1, qas2, qas3, qas4
    ansew = raw_input('>> ')
    if ansew == "1":
        counterSquare = counterSquare + question[1][1]#(+1)
        counterCircle = counterCircle + question[1][2]#(+0)
    elif ansew == "2":
        counterSquare = counterSquare + question[2][1]#(+0)
        counterCircle = counterCircle + question[2][2]#(+1)
    print counterCircle
    print counterSquare


#Gets the current tuple infomation to display (Will be more advanced)
def getQuestion():
    global question
    if messageDisplayed == 0:
        question = qas1
    elif messageDisplayed == 1:
        question = qas2
    elif messageDisplayed == 2:
        question = qas3
    elif messageDisplayed == 3:
        question = qas4
    else:
        print 'youre screwd'

#figures out and prints results
def results():
    print "This is the circle results", counterCircle
    print "This is the square results", counterSquare
    if counterSquare < counterCircle:
        print "You are a circle!"
    elif counterSquare > counterCircle:
        print "You are a square!"
    else:
        print "You are the elusive squircle!"

#mainLoop currently set to 4 questions
hasFile()
while messageDisplayed <=3:
    getQuestion()
    showQaA()
    getResponce()
    messageDisplayed +=1
results()

这是一个很大的代码看,我知道了.当程序首次加载名称qas1时,它会重新确认它是一个元组,但当我尝试将属性传递给'question'时getQuestion():它会忘记它们是什么.任何理想问题是什么？

Answer 1

在第二个文件中，qas[1-4] 都是该函数的本地函数hasFile。让它们成为全局的，你的代码就可以工作了：

def hasFile():
   global qas1, qas2, qas3, qas4
   # etc

第一个代码中也出现相同的错误，但更难注意到 - 四个变量仍然仅在函数中分配 - 这会隐藏同名的全局变量，使它们保持不变。但是，由于加载它们预计不会更改其内容，因此它似乎有效。