如何从手机间隙的纬度和经度获取城市名称？

Question

我可以从当前的经纬度获得完整的地址.但是如何才能从完整地址获取城市名称.这是我的代码.

var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);
//alert("Else loop" + latlng);
geocoder.geocode({
    'latLng': latlng
}, function(results, status) {
    //alert("Else loop1");
    if (status == google.maps.GeocoderStatus.OK) {
        if (results[0]) {
            var add = results[0].formatted_address;
            alert("Full address is: " + add);
        } else {
            alert("address not found");
        }
    } else {
        //document.getElementById("location").innerHTML="Geocoder failed due to: " + status;
        //alert("Geocoder failed due to: " + status);
    }
});

Answer 1

var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);

geocoder.geocode(
    {'latLng': latlng}, 
    function(results, status) {
        if (status == google.maps.GeocoderStatus.OK) {
                if (results[0]) {
                    var add= results[0].formatted_address ;
                    var  value=add.split(",");

                    count=value.length;
                    country=value[count-1];
                    state=value[count-2];
                    city=value[count-3];
                    alert("city name is: " + city);
                }
                else  {
                    alert("address not found");
                }
        }
         else {
            alert("Geocoder failed due to: " + status);
        }
    }
);

用","分隔整个地址作为分隔符并获取城市名称..

Answer 2

Clean example to get location from lat and lang and parsing result. based on Google Reverse Geocoding

 var geocodingAPI = "https://maps.googleapis.com/maps/api/geocode/json?latlng=23.714224,78.961452&key=YOUR_SERVER_API_KEY";

 $.getJSON(geocodingAPI, function (json) {
     if (json.status == "OK") {
         //Check result 0
         var result = json.results[0];
         //look for locality tag and administrative_area_level_1
         var city = "";
         var state = "";
         for (var i = 0, len = result.address_components.length; i < len; i++) {
             var ac = result.address_components[i];
            if (ac.types.indexOf("administrative_area_level_1") >= 0) state = ac.short_name;
         }
         if (state != '') {
             console.log("Hello to you out there in " + city + ", " + state + "!");
         }
     }

 });