Joa*_*sta 8 java authentication spring spring-security
使用Spring Security,我试图从我的CustomUserDetailsService上的loadUserByUsername方法返回我的CustomUser实例中的用户id,就像我获取带有Authentication的Name(get.Name())一样.谢谢你的任何提示!
这是我获取已登录用户的当前名称的方式:
Authentication authentication = SecurityContextHolder.getContext().getAuthentication();
String name = authentication.getName();
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这是CustomUser
public class CustomUser extends User {
private final int userID;
public CustomUser(String username, String password, boolean enabled, boolean accountNonExpired,
boolean credentialsNonExpired,
boolean accountNonLocked,
Collection<? extends GrantedAuthority> authorities, int userID) {
super(username, password, enabled, accountNonExpired, credentialsNonExpired, accountNonLocked, authorities);
this.userID = userID;
}
}
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和我的服务上的loadUserByUsername方法
@Override
public UserDetails loadUserByUsername(String s) throws UsernameNotFoundException {
Usuario u = usuarioDAO.getUsuario(s);
return new CustomUser(u.getLogin(), u.getSenha(), u.isAtivo(), u.isContaNaoExpirada(), u.isContaNaoExpirada(),
u.isCredencialNaoExpirada(), getAuthorities(u.getRegraByRegraId().getId()),u.getId()
);
}
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hol*_*s83 17
Authentication authentication = ...
CustomUser customUser = (CustomUser)authentication.getPrincipal();
int userId = customUser.getUserId();
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getUserId()如果您还没有getter方法,则必须添加它.
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