ame*_*lon 81 javascript angularjs angularjs-ng-repeat ng-filter
看起来像一个非常基本的问题,但我无法正确的语法..
<li class="list-group-item" ng-repeat="question in newSection.Questions | filter:Id != '-1'; " ng-mouseenter="hover = true" ng-mouseleave="hover = false">
<div href="#" editable-text="question.Text">{{question.Text}}</div>
</li>
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我想要的只是显示id为非-1的所有问题.我究竟做错了什么.谢谢!
Mic*_*ose 161
语法稍微偏离,尝试:
<li class="list-group-item"
ng-repeat="question in newSection.Questions | filter:{ Id: '!-1'}"
ng-mouseenter="hover = true" ng-mouseleave="hover = false">
<div href="#" editable-text="question.Text">{{question.Text}}</div>
</li>
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看一点JSFiddle:http://jsfiddle.net/U3pVM/3845/
编辑:
变量示例:
<script> var invalidId = '-1'; </script>
<li class="list-group-item"
ng-repeat="question in newSection.Questions | filter:{ Id: '!' + invalidId}"
ng-mouseenter="hover = true" ng-mouseleave="hover = false">
<div href="#" editable-text="question.Text">{{question.Text}}</div>
</li>
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Fer*_*osa 20
尽管@Michael Rose的回答适用于这种情况,但如果您尝试过滤不等于某个对象/变量,我认为不会
在这种情况下,您可以使用:
JS:
filterId = -1
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HTML:
<li ng-repeat="question in newSection.Questions | filter: !{ Id: filterId}">
</li>
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一个更嵌套的案例:
JS:
someQuestion = {
someObject: {
Id: 1
}
}
newSection.Questions = [someQuestion]
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HTML
<li ng-repeat="question in newSection.Questions | filter: !{someObject : {Id: -1} }">
</li>
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