将C++二维固定长度char数组编组为结构成员

Question

我试图调用一个非托管C++函数,它具有一个结构作为输入参数.结构在头文件中定义如下:

struct MyStruct
{
int     siOrder;
char     aaszNames[6][25];
int     siId[6];
int     siTones[6];        
};

我试图将托管结构声明如下:

[StructLayoutAttribute(LayoutKind.Sequential, CharSet=CharSet.Ansi)]
public struct MyStruct {

public int siOrder;

[MarshalAsAttribute(UnmanagedType.ByValTStr, SizeConst=150)]
public string aaszNames;

[MarshalAsAttribute(UnmanagedType.ByValArray, SizeConst=6, ArraySubType=UnmanagedType.I4)]
public int[] siId;

[MarshalAsAttribute(UnmanagedType.ByValArray, SizeConst=6, ArraySubType=UnmanagedType.I4)]
public int[] siTones;
}

但没有任何成功.我猜测编组失败了,因为aaszNames实际上是一个由六个25长的空终止字符串组成的数组.我尝试将aaszNames声明为

 [MarshalAsAttribute(UnmanagedType.ByValArray, SizeConst=150)]
 public char[] aaszNames;

必要时用空值填充数组.但是,再一次,没有.

有什么我想念的吗？我错了什么？编组这个2-D char数组的最佳方法是什么？

请给我任何提示.

Answer 1

尝试使用多个C#结构:

[StructLayoutAttribute(LayoutKind.Sequential, CharSet=CharSet.Ansi)]
public struct MyStruct_Name
{
    [MarshalAsAttribute(UnmanagedType.ByValTStr, SizeConst = 25)]
    public string name;
}

[StructLayoutAttribute(LayoutKind.Sequential, CharSet = CharSet.Ansi)]
public struct MyStruct
{
    public int siOrder;

    [MarshalAsAttribute(UnmanagedType.ByValArray, SizeConst = 6)]
    public MyStruct_Name aaszNames;

    [MarshalAsAttribute(UnmanagedType.ByValArray, SizeConst = 6, ArraySubType = UnmanagedType.I4)]
    public int[] siId;

    [MarshalAsAttribute(UnmanagedType.ByValArray, SizeConst = 6, ArraySubType = UnmanagedType.I4)]
    public int[] siTones;
}

这就是我传递C风格字符串数组的方式.

别忘了创建aaszNames的内容!marshaller讨厌空引用.

MyStruct foo = new MyStruct();
for (int i = 0; i < 6; i++)
{
    foo.aaszNames[i] = new MyStruct_Name();
    foo.aaszNames[i].name = "";
}

祝好运!