Gia*_*oli 6 google-visualization google-chartwrapper
我是谷歌可视化的新手.我正在开发一个完整的仪表板,如谷歌完整的仪表板示例
按照示例,我声明如下数据:
var data = google.visualization.arrayToDataTable([
['CodiceCliente', 'Cliente', 'QtàO13', 'QtàO14','UM'],
['0000038893', 'Coop',300,350, 'CT'] .... ]);
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现在我想从服务器加载数据.我像这样创建一个Json:
{
"cols": [
{"id": "codiceCliente","label": "Cod. Cliente","type": "string"},
{"id": "clienteDesc","label": "Cliente","type": "string"},
{"id": "qtaO13","label": "Qtà O13","type": "number"},
{"id": "qtaO14","label": "Qtà O14","type": "number"},
{"id": "um","label": "UM","type": "string"}
],
"rows": [
{
"c": [
{"v": "0000038893"},
{"v": "Coop"},
{"v": "300"},
{"v": "350"},
{"v": "CT"} ]
},
{.... }, ... ]}
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在html页面中,我使用此代码从服务器获取数据:
var jsonData = $.ajax({
url: "getJson.do",
dataType:"json",
async: false
}).responseText;
var data = google.visualization.DataTable(jsonData);
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当我打开页面时,我收到此错误:"对象#没有方法'zg'格式+它,默认+它,ui +它,控制+它,核心图+ it.I.js:183"
我哪里错了?JSON格式错了?
您缺少newDataTable构造函数中的关键字.它应该是:
var data = new google.visualization.DataTable(jsonData);
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