Rey*_*rPM 3 php doctrine symfony doctrine-orm
我有两张桌子company(id, ...)和company_has_wtax(company_id, ....). 我需要获取所有不在company_has_wtax表格中的公司。在原始 SQL 中应该是这样的:
SELECT id FROM company LEFT JOIN (company_has_wtax)
ON company.id = company_has_wtax.company_id
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但我不知道如何在 DQL for Doctrine 上构建它,有什么帮助吗?
将方法添加到存储库并从控制器调用它
这是我在@Javad 回答离开后制作的代码:
public function findCompanyByDocument() {
$q2 = $this->createQueryBuilder('ApprovalBundle:CompanyHasWtax c2');
$query = $this->createQueryBuilder('c')
->leftJoin('c.CompanyHasWtax', 'chw')
->where($query->expr()->notIn('c.id', $q2->select('c2.company')->getDQL())
);
echo $query->getQuery()->getSQL();
// return $query->getQuery()->getResult();
}
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这就是我在控制器中调用它的方式:
$em = $this->getDoctrine()->getManager();
$entities = $em->getRepository('RegisterCompanyBundle:Company')->findCompanyByDocument();
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但我收到此错误:
ContextErrorException:注意:未定义的变量:在 /var/www/html/kraken/src/Company/RegisterCompanyBundle/Entity/Repository/CompanyRepository.php 第 40 行中查询
第 40 行在哪里->where($query->expr()->notIn('c.id', $q2->select('c2.company')->getDQL())。
这是实体:
Company.php
class Company {
/**
* @ORM\Id
* @ORM\Column(type="integer", unique=true, nullable=false)
* @ORM\GeneratedValue
*
*/
protected $id;
/**
* @ORM\Column(name="legal_name",type="string",nullable=false,length=255)
* @Assert\NotBlank(message="Este valor no debería estar vacío.")
* @Assert\Regex("/^[a-zA-Z0-9ñÑÁÉÍÓÚñáéíóú\s\,]+$/", message="Este valor debería ser de tipo alfanumérico.")
*/
protected $legalName;
/**
* @ORM\Column(name="social_reason",type="string",nullable=false,length=255)
* @Assert\NotBlank(message="Este valor no debería estar vacío.")
* @Assert\Regex("/^[a-zA-Z0-9ñÑÁÉÍÓÚñáéíóú\s\,]+$/", message="Este valor debería ser de tipo alfanumérico.")
*/
protected $socialReason;
/**
* @ORM\Column(name="tax_id",type="string",nullable=false)
* @Assert\NotBlank(message="Este valor no debería estar vacío.")
* @Assert\Regex("/^[\d{9}$]/", message="Este valor debería tener exactamente 9 caracteres.")
*/
protected $taxId;
/**
* @ORM\OneToOne(targetEntity="Common\MediaBundle\Entity\Media")
* @ORM\JoinColumn(name="logo", referencedColumnName="id")
*/
protected $logo;
/**
* @ORM\OneToOne(targetEntity="Common\MediaBundle\Entity\Media")
* @ORM\JoinColumn(name="banner", referencedColumnName="id")
*/
protected $banner;
/**
* @ORM\OneToOne(targetEntity="Company\RegisterCompanyBundle\Entity\NCompanyType")
* @ORM\JoinColumn(name="type", referencedColumnName="id")
*/
protected $type;
/**
* @ORM\OneToOne(targetEntity="Company\RegisterCompanyBundle\Entity\NCompanyStatus")
* @ORM\JoinColumn(name="status", referencedColumnName="id")
*/
protected $status;
/**
* @ORM\Column(type="integer",nullable=false,length=1)
*/
protected $certified;
}
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CompanyHasWtax.php
class CompanyHasWtax {
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="\Company\RegisterCompanyBundle\Entity\Company")
* @ORM\JoinColumn(name="company", referencedColumnName="id")
*/
protected $company;
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="\Configuration\FeeBundle\Entity\Fee")
* @ORM\JoinColumn(name="wtax", referencedColumnName="id")
*/
protected $wtax;
/**
* @ORM\Id
* @ORM\ManyToOne(targetEntity="\User\SecurityBundle\Entity\User")
* @ORM\JoinColumn(name="kuser", referencedColumnName="id")
*/
protected $user;
/**
* @ORM\Column(name="from_date", type="datetime")
*/
protected $from_date;
/**
* @ORM\Column(name="to_date", type="datetime")
*/
protected $to_date;
}
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丑陋的解决方案
我找到了一种方法来让这个工作,但它对我来说很难看,而且有人说我这样做是不对的:
public function findCompanyByDocument() {
$sql = "SELECT * FROM company c WHERE c.id NOT IN (SELECT chm.company FROM company_has_media chm WHERE chm.company = c.id)";
$em = $this->getEntityManager();
return $em->getConnection()->fetchAll($sql);
}
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尝试这个:
$q2 = $this->createQueryBuilder('c')
->select('IDENTITY(c2.company)')
->join('RegisterCompanyBundle:CompanyHasMedia', 'c2', 'WITH', 'c2.company = c.id');
$query = $this->createQueryBuilder('c3');
$query->where($query->expr()->notIn('c3.id', $q2->getDQL()));
$companies = $query->getQuery()->getResult();
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请注意,我们通过 reversedBy/mappedBy 从一个非相关实体创建查询
我们需要对相关表的特定字段使用 IDENTIY
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