将行值计为列名mysql

Question

我有桌子 user_completed

CREATE TABLE IF NOT EXISTS `user_completed` (
  `rowId` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `designer_id` int(10) unsigned NOT NULL,
  `status` varchar(54) DEFAULT NULL,
  PRIMARY KEY (`rowId`),
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ;


INSERT INTO `user_completed` (`rowId`, `designer_id`, `status`) VALUES
(1, 1, accept),
(2, 1, reject),
(3, 1, accept),
(4, 1, reject),
(5, 1, overtime),
(6, 2, accept)
(7, 2, accept)
(8, 3, accept)
(9, 2, reject);

看起来像:

rowId   designer_id    status 
1           1          accept
2           1          reject
3           1          accept
4           1          reject
5           1          overtime
6           2          accept
7           2          accept
8           3          accept
9           2          reject

我想得到以下结果:

designer_id   accept   overtime   reject
1             2        1          2
2             2        0          1
3             1        0          0

但我不知道如何分组designer_id然后计数不同status,每个分成如上所述的列.

Answer 1

试试这个

SELECT  designer_id,
    SUM(IF(status = 'accept',1,0)) as 'Accept',
    SUM(IF(status = 'reject',1,0)) as 'Reject',
    SUM(IF(status = 'overtime',1,0)) as 'Overtime'
FROM 
    user_completed
Group By designer_id

小提琴演示

正如杰克所说,这简直就是这样

SELECT  designer_id,
    SUM(status = 'accept') as 'Accept',
    SUM(status = 'reject') as 'Reject',
    SUM(status = 'overtime') as 'Overtime'
FROM 
    user_completed
Group By designer_id

小提琴演示