问题:我想维护文件的"集合".这将有助于构建时间和灵活性.例如,每当我编辑我的app.js文件时,我都不想重新编译我的所有twitter引导程序文件.
我当然可以通过2个任务和2个监视声明实现这一点 - 问题是除了文件数组之外,任务是相同的.理想情况下,我想在watch声明中传递这些作为参数有没有办法做类似下面的伪代码?:
var files = {
scripts: [
'www/assets/scripts/plugins/**/*.js',
'www/assets/scripts/main.js',
],
vendor: [
'vendor/jquery/dist/jquery.js',
'vendor/jqueryui/ui/jquery.ui.widget.js',
'vendor/holderjs/holder.js'
],
};
...
gulp.task('js', ['lint'], function (files, output) {
return gulp.src(files)
.pipe(debug())
.pipe(concat(output))
.pipe(uglify({outSourceMap: true}))
.pipe(gulp.dest(targetJSDir))
.pipe(notify('JS minified'))
.on('error', gutil.log)
});
...
gulp.watch('scripts/**/*.js', ['lint', 'js'], files.scripts, 'app.min.js');
gulp.watch('vendor/**/*.js', ['lint', 'js'], files.vendor, 'vendor.min.js');
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翻转另一种方式:是命名空间调用任务的监视声明吗?这样我可以检查哪个手表触发了任务,并以任务本身为条件.
问题是除了文件数组之外,任务是相同的.
我相信lazypipe(见其gh页面)非常适合您的需求.这是一个有趣的问题.我将尝试回答我认为你所问的问题(lazypipe满意)以及我认为你可能正在考虑的内容,或者如果你超过管道的参数化将最终考虑问题.
我们想要的一个方面是我们不想在没有改变的文件上重新运行jshint.此外,我们希望保持DRY,除了更改的文件之外,我们还想要获取新文件.
这是经过测试并适用于我:
var gulp = require('gulp');
var $ = require('gulp-load-plugins')();
var es = require('event-stream');
var lazypipe = require('lazypipe');
var gutil = require('gulp-util');
var path = require('path');
var files = {
scripts: ['src/**/*.js'],
vendor: ['vendor/**/*.js']
};
// sets up a lazy pipe that does jshint related stuff
function getJsMultiPipe(name) {
return lazypipe()
.pipe($.jshint)
.pipe($.jshint.reporter, 'jshint-stylish')
// if you don't want to fail on style errors remove/comment this out:
.pipe($.jshint.reporter, 'fail');
}
// sets up a lazy pipe that does concat and post-concat stuff
function getJsCombinedPipe(groupName, outfile) {
return lazypipe()
.pipe($.concat, outfile)
.pipe($.uglify, {outSourceMap: true})
.pipe(gulp.dest, 'build')
.pipe($.notify, {message: groupName + ' JS minified', onLast: true});
}
// sets up a pipe for the initial build task, combining the above two pipes
function getBuildPipe(groupName, outfile) {
return gulp.src(files[groupName])
.pipe(getJsMultiPipe(groupName)())
.pipe(getJsCombinedPipe(groupName, outfile)());
}
// sets up a watch pipe, such that only the changed file is jshinted,
// but all files are included in the concat steps
function setWatchPipe(groupName, outfile) {
return $.watch({
glob: files[groupName],
name: groupName,
emitOnGlob: false,
emit: 'one'
}, function(file, done) {
return file
.pipe($.debug({title: 'watch -- changed file'}))
.pipe(getJsMultiPipe(groupName)())
// switch context
.pipe(gulp.src(files[groupName]))
.pipe($.debug({title: 'watch -- entire group'}))
.pipe(getJsCombinedPipe(groupName, outfile)())
.pipe($.debug({title: 'watch -- concatted/source-mapped'}))
.pipe($.notify({message: 'JS minified', onLast: true}));
});
}
// task to do an initial full build
gulp.task('build', function() {
return es.merge(
getBuildPipe('scripts', 'app.min.js'),
getBuildPipe('vendor', 'vendor.min.js')
)
.pipe($.notify({message: 'JS minified', onLast: true}));
});
// task to do an initial full build and then set up watches for
// incremental change
gulp.task('watch', ['build'], function(done) {
setWatchPipe('scripts', 'app.min.js');
setWatchPipe('vendor', 'vendor.min.js');
done();
});
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我的依赖关系看起来像:
"devDependencies": {
"jshint-stylish": "^0.1.5",
"gulp-concat": "^2.2.0",
"gulp-uglify": "^0.2.1",
"gulp-debug": "^0.3.0",
"gulp-notify": "^1.2.5",
"gulp-jshint": "^1.5.3",
"gulp": "^3.6.0",
"gulp-load-plugins": "^0.5.0",
"lazypipe": "^0.2.1",
"event-stream": "^3.1.1",
"gulp-util": "^2.2.14",
"gulp-watch": "^0.5.3"
}
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编辑:我再次瞥了一眼,我注意到这些线条:
// switch context
.pipe(gulp.src(files[groupName]))
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请注意,我相信自从我写这篇文章以来gulp.src API已经发生了变化,并且当你将内容输入gulp.src时它当前没有切换上下文,因此这个地方可能需要更改.对于较新版本的gulp,我认为会发生的是你将添加到上下文中,相反可能会失去一点点效率.