考虑下面我的SQL查询; 它为同一个参数调用两次.这是重复服务器完成的工作.有一个更好的方法吗?
SELECT Status_Detail_Code, count(*) as
[Number of times assigned], round(sum(Duration)/60,2) as [total duration Hr]
FROM dbo.V_TIMELINE
WHERE (CADATE > N'20080101')
group by Status_Detail_Code order by sum(Duration) desc
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Qua*_*noi 15
不,SQL Server重用聚合.
实际上,如果构建查询计划,您将看到SUM聚合运算符(如Stream Aggregate)表示为类似的结果集Expr****.
此表达式的值稍后将用作其他运算符的输入.
这是示例查询:
SELECT ROUND(SUM(id), -1)
FROM master
GROUP BY
name
ORDER BY
SUM(id) DESC
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它的计划是:
|--Compute Scalar(DEFINE:([Expr1004]=round([Expr1003],(-1))))
|--Sort(ORDER BY:([Expr1003] DESC))
|--Stream Aggregate(GROUP BY:([test].[dbo].[master].[name]) DEFINE:([Expr1003]=SUM([test].[dbo].[master].[id])))
|--Index Scan(OBJECT:([test].[dbo].[master].[ix_name_desc]), ORDERED BACKWARD)
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如您所见,聚合完成一次并存储在其中Expr1003.
Expr1003然后在Sort运算符(处理ORDER BY)和Compute Scalar(处理ROUND)中重用
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