显示半小时范围内的小时数

Question

我正在制作一个约会脚本,从数据库开始和关闭时间,然后显示开始和结束时间之间的时间来预订会议,每次会议只能预订半小时,所以我需要显示这样的时间使用单选按钮

9:00am  - 9:30am
9:30am  - 10:00am
10:00am - 10:30am
...
...
...

我能够计算办公室开放的总小时数,并且使用for循环我能够显示时间

$office_start_time = '09:00:00';
$office_end_time = '16:00:00';

$start = explode(':', $office_start_time);
$end = explode(':', $office_end_time);
$total_hours = $end[0] - $start[0] - ($end[1] < $start[1]);
echo 'total hours: '.$total_hours;
echo '<br>';
//exit;
?>
<table class="table table-hover table-bordered">
    <tbody>
    <?php for ($i = 0; $i < $total_hours; $i++) {
        echo "<input name='time' type='radio' value='09:00|09:30'> 9:00am-9:30am<br/>";
        ?>

    <?php } ?>
    </tbody>
</table>

我的问题是上面的代码给了我一个像下面的输出,我坚持如何获得正确的结果

如果我能得到一些关于如下显示时间的帮助,我将非常感激

9:00am  - 9:30am
9:30am  - 10:00am
10:00am - 10:30am
...
...
...

Answer 1

$start    = new DateTime('09:00:00');
$end      = new DateTime('16:00:01'); // add 1 second because last one is not included in the loop
$interval = new DateInterval('PT30M');
$period   = new DatePeriod($start, $interval, $end);

$previous = '';
foreach ($period as $dt) {
    $current = $dt->format("h:ia");
    if (!empty($previous)) {
        echo "<input name='time' type='radio' value='{$previous}|{$current}'> {$previous}-{$current}<br/>";
    }
    $previous = $current;
}

看到它在行动

Answer 2

strtotime的魔法可以做到这一点

$start = '09:00:00';
$end = '16:00:00';
$time = strtotime($start);
$timeStop = strtotime($end);

while($time<$timeStop) {
    echo date('H:i', $time);
    $time = strtotime('+30 minutes', $time);
    echo ' - ' . date('H:i', $time) . '<br/>';
}

结果：

09:30 - 10:00
10:00 - 10:30
10:30 - 11:00
11:00 - 11:30
11:30 - 12:00
12:00 - 12:30
12:30 - 13:00
13:00 - 13:30
13:30 - 14:00
14:00 - 14:30
14:30 - 15:00
15:00 - 15:30
15:30 - 16:00