在gdb中逐字打印整个字符串

Question

我在gdb中打印一个字符串(char*)

(gdb) p l
l=0x9aa1f48 "up2 129104596496602200 19 0 0 3 0 eth1 XX :001CB",'0' <repeats 12 times>, "DC"

是否有设置p打印整个字符串,而不是填写"重复......".在它的同时 - 也扩展了字符串的默认可打印长度,p如果字符串很长,似乎会切断.

Answer 1

set print repeats 0

例:

(gdb) p "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
$6 = 'a' <repeats 30 times>
(gdb) set print repeats 0
(gdb) p "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
$7 = "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
(gdb) set print repeats 10
(gdb) p "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
$8 = 'a' <repeats 30 times>

Answer 2

像这样使用gdb的printf命令:

(gdb) printf "%s\n", a
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

代替

(gdb) p a  
$1 = 'a' <repeats 32 times>