无法通过不合逻辑的线pep8错误

Question

我一直试图解决这个问题一段时间,我不能让它通过pep8.这是我的代码:

1.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and 
    sum(regex.count(char) for char in splitter) == 1 and 
    regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

2.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and 
    sum(regex.count(char) for char in splitter) == 1 and 
    regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

3.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' 
    and regex.count('(') > 1):

    print('hi')

我在3个if语句中得到以下PEP8错误:

E125 continuation line does not distinguish itself from next logical line

有什么问题吗？线条用第一个支架缩进,所以我真的没有线索.

Answer 1

1.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and
        sum(regex.count(char) for char in splitter) == 1 and
        regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

2.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and
        sum(regex.count(char) for char in splitter) == 1 and
        regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

3.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')'
        and regex.count('(') > 1):

    print('hi')