检查是否在python中按下了按钮？

Question

代码：

import sys
from tkinter import *

credit = 0
coins = 0
choice = 0


credit1 = 0
coins = 0
prices = [200,150,160,50,90]
item = 0
i = 0
temp=0
n=0
choice1 = 0
choice2 = 0

credit1 = 0
coins = 0
prices = [200,150,160,50,90]
item = 0
i = 0
temp=0
n=0
choice1 = 0
choice2 = 0

def insert():
    insert = Tk()

    insert.geometry("450x250")
    iLabel = Label(insert, text="Enter coins.[Press Buttons]").grid(row=1, column=1)

    tenbutton = Button(insert, text="10p").grid(row=2, column=1)
    twentybutton = Button(insert, text="20p").grid(row=3, column=1)
    fiftybutton = Button(insert, text="50p").grid(row=4, column=1)
    poundbutton = Button(insert, text="£1").grid(row=5, column=1)

我正在创建一个模拟自动售货机的程序。我如何告诉 Python “检查”是否按下了 A 按钮？在伪代码中，它将是：

if tenbutton is pressed:
   Add 10p to credit

“如果按下十个按钮”，我将如何用 Python 编写？先感谢您。

Answer 1

很简单，定义一个在按钮按下后将被调用的函数。像这样：

def addCredit():
    global credit
    credit+=10

然后将这个简单的功能分配给您的按钮：

tenbutton = Button(insert, text="10p", command=addCredit).grid(row=2, column=1)

顺便说一句，您的代码严重要求class某个地方。使用这么多全局变量通常是一种不好的做法。另一个挑剔的是from tkinter import *，它破坏了可读性。我建议import tkinter as tk。