从Android应用程序上传多个图像文件到PHP服务器

Ill*_*ent 6 php android cakephp file-upload

我是android编程的新手.我一直在尝试使用以下代码将多个图像从我的应用程序上传到服务器.这里image []数组与namevaluepair中的用户名,密码等其他数据一起发布到服务器.

Java代码:

public void post(String url, List<NameValuePair> nameValuePairs) {
    HttpClient httpClient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost(url);
    try {
        MultipartEntity entity = new MultipartEntity(
        HttpMultipartMode.BROWSER_COMPATIBLE);
        for (int index = 0; index < nameValuePairs.size(); index++) {
            if (nameValuePairs.get(index).getName()
                    .equalsIgnoreCase("image[]")) {
                // If the key equals to "image[]", we use FileBody to transfer
                // the data
                Log.d("key", "image");
                Log.d("image path", nameValuePairs.get(index).getName());
                entity.addPart(nameValuePairs.get(index).getName(),
                        new FileBody(new File(nameValuePairs.get(index)
                                .getValue())));

            } else {
                // Normal string data
                Log.d("tag", nameValuePairs.get(index).getName());
                // Log.d("tag", nameValuePairs.get(index).getValue());
                entity.addPart(
                        nameValuePairs.get(index).getName(),
                        new StringBody(nameValuePairs.get(index).getValue()));
            }
        }
        httpPost.setEntity(entity);
        HttpResponse response = httpClient.execute(httpPost);
        HttpEntity enttiy = response.getEntity();
        Log.d("server response to post data", EntityUtils.toString(enttiy));
    } catch (IOException e) {
        e.printStackTrace();
    }
}
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PHP代码(工作版):

<?php
$target_path = "user_uploaded_photos/";
for($i=0;$i<count($_FILES["image"]["name"]);$i++){
$fileData = pathinfo(basename($_FILES["image"]["name"][$i]));
$username = $_POST['username'];
print_r($fileData);
$date = date('Y_m_d_H_i_s');
$newfilename = $username.$i.$date.".".$fileData['extension'];
if (move_uploaded_file($_FILES["image"]["tmp_name"][$i], $target_path."/".$newfilename))
{
    echo "The image {$_FILES['image']['name'][$i]} was successfully uploaded and added to the gallery<br />";
}
else
{
 echo "There was an error uploading the file {$_FILES['image']['name'][$i]}, please try again!<br />";
}
} $location = $_POST['location'];
//other fields and database operations ommitted
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我的问题在于我们正在使用的cakephp网站.对于cake php,我使用名称值对,如下所示:

nameValuePair
         .add(new BasicNameValuePair("UserDatum[user_id]", "2"));
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像这样发送字符串值对我有用.但是当我声明images []数组图像被上传但无法从$ _FILES访问时.我已声明images []数组如下:

for (String s : imagePath) {
            nameValuePair.add(new BasicNameValuePair("UserDatum[images][]",
                    s));
            Log.d("image-path", s);
        }
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这里imagePath是包含图像路径的字符串的arrayList.在应用程序中以正确的方式声明"UserDatum [images] []"吗?它适用于发布的php,但在蛋糕php只发布字符串值而不是图像.我尝试过像ion这样的其他图书馆 .但我只能在不使用数组结构的情况下上传一张照片.请评论或指出我在一个帖子中发布多个图像和字符串的正确方向.

小智 0

每当我从应用程序发布图像数据时,我都会使用 Base64 编码图像(请参阅:Android post Base64 String to PHP

这可能会给你一个更好的路线。