gaw*_*wry 19 python pycurl httplib2 httplib python-requests
我正在使用python中的请求库发出HTTP请求,但是我需要来自响应http请求的服务器的ip地址,并且我试图避免进行两次调用(并且可能有一个不同的ip地址来自响应的那个请求.
那可能吗?有没有python http库允许我这样做?
ps:我还需要发出HTTPS请求并使用经过身份验证的代理.
更新1:
例:
import requests
proxies = {
"http": "http://user:password@10.10.1.10:3128",
"https": "http://user:password@10.10.1.10:1080",
}
response = requests.get("http://example.org", proxies=proxies)
response.ip # This doesn't exist, this is just an what I would like to do
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那么,我想知道从响应中的方法或属性连接的IP地址请求.在其他库中,我能够通过找到sock对象并使用getpeername()方法来做到这一点.
Mat*_*ttH 33
事实证明它相当复杂.
使用requests版本1.2.3 时,这是一个猴子补丁:
缠绕_make_request方法上HTTPConnectionPool存储从响应socket.getpeername()该HTTPResponse实例.
对于我在python 2.7.3上,这个实例可用response.raw._original_response.
from requests.packages.urllib3.connectionpool import HTTPConnectionPool
def _make_request(self,conn,method,url,**kwargs):
response = self._old_make_request(conn,method,url,**kwargs)
sock = getattr(conn,'sock',False)
if sock:
setattr(response,'peer',sock.getpeername())
else:
setattr(response,'peer',None)
return response
HTTPConnectionPool._old_make_request = HTTPConnectionPool._make_request
HTTPConnectionPool._make_request = _make_request
import requests
r = requests.get('http://www.google.com')
print r.raw._original_response.peer
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产量:
('2a00:1450:4009:809::1017', 80, 0, 0)
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啊,如果涉及代理或响应被分块,HTTPConnectionPool._make_request则不会被调用.
所以这是一个新版本修补httplib.getresponse:
import httplib
def getresponse(self,*args,**kwargs):
response = self._old_getresponse(*args,**kwargs)
if self.sock:
response.peer = self.sock.getpeername()
else:
response.peer = None
return response
httplib.HTTPConnection._old_getresponse = httplib.HTTPConnection.getresponse
httplib.HTTPConnection.getresponse = getresponse
import requests
def check_peer(resp):
orig_resp = resp.raw._original_response
if hasattr(orig_resp,'peer'):
return getattr(orig_resp,'peer')
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运行:
>>> r1 = requests.get('http://www.google.com')
>>> check_peer(r1)
('2a00:1450:4009:808::101f', 80, 0, 0)
>>> r2 = requests.get('https://www.google.com')
>>> check_peer(r2)
('2a00:1450:4009:808::101f', 443, 0, 0)
>>> r3 = requests.get('http://wheezyweb.readthedocs.org/en/latest/tutorial.html#what-you-ll-build')
>>> check_peer(r3)
('162.209.99.68', 80)
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还检查了运行时是否设置了代理; 代理地址被退回.
更新 2016/01/19
rsp = requests.get('http://google.com', stream=True)
# grab the IP while you can, before you consume the body!!!!!!!!
print rsp.raw._fp.fp._sock.getpeername()
# consume the body, which calls the read(), after that fileno is no longer available.
print rsp.content
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更新 2016/05/19
根据评论,复制到这里以获得可见性,Richard Kenneth Niescior提供了以下确认使用请求2.10.0和Python 3.
rsp=requests.get(..., stream=True)
rsp.raw._connection.sock.getpeername()
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更新 2019/02/22
请求版本为2.19.1的Python3.
rsp=requests.get(..., stream=True)
resp.raw._connection.sock.socket.getsockname()
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