如何将JSON对象转换为Custom C#对象？

Question

有没有一种简单的方法来填充我的C#对象与通过AJAX传递的JSON对象？

//这是使用JSON.stringify从页面传递给C#WEBMETHOD的JSON对象

{
    "user": {
        "name": "asdf",
        "teamname": "b",
        "email": "c",
        "players": ["1", "2"]
    }
}

// C#WebMetod接收JSON对象

[WebMethod]
public static void SaveTeam(Object user)
{

}

// C#类,表示传入WebMethod的JSON Object的对象结构

public class User
{
    public string name { get; set; }
    public string teamname { get; set; }
    public string email { get; set; }
    public Array players { get; set; }
}

Answer 1

在C#中使用JSON的好方法是使用JSON.NET

快速入门和API文档从 JSON.NET -官方网站帮助你使用它.

如何使用它的一个例子:

public class User
{
    public User(string json)
    {
        JObject jObject = JObject.Parse(json);
        JToken jUser = jObject["user"];
        name = (string) jUser["name"];
        teamname = (string) jUser["teamname"];
        email = (string) jUser["email"];
        players = jUser["players"].ToArray();
    }

    public string name { get; set; }
    public string teamname { get; set; }
    public string email { get; set; }
    public Array players { get; set; }
}

// Use
private void Run()
{
    string json = @"{""user"":{""name"":""asdf"",""teamname"":""b"",""email"":""c"",""players"":[""1"",""2""]}}";
    User user = new User(json);

    Console.WriteLine("Name : " + user.name);
    Console.WriteLine("Teamname : " + user.teamname);
    Console.WriteLine("Email : " + user.email);
    Console.WriteLine("Players:");

    foreach (var player in user.players)
        Console.WriteLine(player);
 }

Answer 2

因为我们都喜欢一个内衬代码

Newtonsoft比java脚本序列化器更快....这个依赖于Newtonsoft NuGet包,它比默认的序列化器更受欢迎.

如果我们有课,那么使用下面.

Mycustomclassname oMycustomclassname = Newtonsoft.Json.JsonConvert.DeserializeObject<Mycustomclassname>(jsonString);

没有班级然后使用动态

var oMycustomclassname = Newtonsoft.Json.JsonConvert.DeserializeObject<dynamic>(jsonString);

Answer 3

为了保持打开选项,如果您使用的是.NET 3.5或更高版本,这里有一个完整的示例,您可以直接使用Generics从框架中使用.正如其他人所提到的,如果它不仅仅是简单的对象,你应该真正使用JSON.net.

public static string Serialize<T>(T obj)
{
    DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
    MemoryStream ms = new MemoryStream();
    serializer.WriteObject(ms, obj);
    string retVal = Encoding.UTF8.GetString(ms.ToArray());
    return retVal;
}

public static T Deserialize<T>(string json)
{
    T obj = Activator.CreateInstance<T>();
    MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(json));
    DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
    obj = (T)serializer.ReadObject(ms);
    ms.Close();
    return obj;
}

你需要:

using System.Runtime.Serialization;

using System.Runtime.Serialization.Json;

Answer 4

鉴于您的代码示例,您不需要做任何其他事情.

如果将该JSON字符串传递给Web方法,它将自动解析JSON字符串并创建一个填充的User对象作为SaveTeam方法的参数.

通常,您可以使用JavascriptSerializer下面的类,或者为了更加灵活,可以使用任何各种Json框架(Jayrock JSON是一个很好的框架)来轻松实现JSON操作.

 JavaScriptSerializer jss= new JavaScriptSerializer();
 User user = jss.Deserialize<User>(jsonResponse); 

Answer 5

另一个非常简单的解决方案是使用Newtonsoft.Json库:

User user = JsonConvert.DeserializeObject<User>(jsonString);

Answer 6

以下两个示例使用了其中一个

1. System.Web.Script.Serialization下的JavaScriptSerializer或
2. 在System.Web.Helpers下的Json.Decode

示例1:使用System.Web.Script.Serialization

using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Script.Serialization;

namespace Tests
{
    [TestClass]
    public class JsonTests
    {
        [TestMethod]
        public void Test()
        {
            var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            dynamic jsonObject = serializer.Deserialize<dynamic>(json);

            dynamic x = jsonObject["user"]; // result is Dictionary<string,object> user with fields name, teamname, email and players with their values
            x = jsonObject["user"]["name"]; // result is asdf
            x = jsonObject["user"]["players"]; // result is object[] players with its values
        }
    }
}

用法: JSON对象为Custom C#对象

using System;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Script.Serialization;
using System.Linq;

namespace Tests
{
    [TestClass]
    public class JsonTests
    {
        [TestMethod]
        public void TestJavaScriptSerializer()
        {
            var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
            User user = new User(json);
            Console.WriteLine("Name : " + user.name);
            Console.WriteLine("Teamname : " + user.teamname);
            Console.WriteLine("Email : " + user.email);
            Console.WriteLine("Players:");
            foreach (var player in user.players)
                Console.WriteLine(player);
        }
    }

    public class User {
        public User(string json) {
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            var jsonObject = serializer.Deserialize<dynamic>(json);
            name = (string)jsonObject["user"]["name"];
            teamname = (string)jsonObject["user"]["teamname"];
            email = (string)jsonObject["user"]["email"];
            players = jsonObject["user"]["players"];
        }

        public string name { get; set; }
        public string teamname { get; set; }
        public string email { get; set; }
        public Array players { get; set; }
    }
}

示例2:使用System.Web.Helpers

using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Helpers;

namespace Tests
{
    [TestClass]
    public class JsonTests
    {
        [TestMethod]
        public void TestJsonDecode()
        {
            var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
            dynamic jsonObject = Json.Decode(json);

            dynamic x = jsonObject.user; // result is dynamic json object user with fields name, teamname, email and players with their values
            x = jsonObject.user.name; // result is asdf
            x = jsonObject.user.players; // result is dynamic json array players with its values
        }
    }
}

用法: JSON对象为Custom C#对象

using System;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.Web.Helpers;
using System.Linq;

namespace Tests
{
    [TestClass]
    public class JsonTests
    {
        [TestMethod]
        public void TestJsonDecode()
        {
            var json = "{\"user\":{\"name\":\"asdf\",\"teamname\":\"b\",\"email\":\"c\",\"players\":[\"1\",\"2\"]}}";
            User user = new User(json);
            Console.WriteLine("Name : " + user.name);
            Console.WriteLine("Teamname : " + user.teamname);
            Console.WriteLine("Email : " + user.email);
            Console.WriteLine("Players:");
            foreach (var player in user.players)
                Console.WriteLine(player);
        }
    }

    public class User {
        public User(string json) {
            var jsonObject = Json.Decode(json);
            name = (string)jsonObject.user.name;
            teamname = (string)jsonObject.user.teamname;
            email = (string)jsonObject.user.email;
            players = (DynamicJsonArray) jsonObject.user.players;
        }

        public string name { get; set; }
        public string teamname { get; set; }
        public string email { get; set; }
        public Array players { get; set; }
    }
}

此代码需要添加System.Web.Helpers命名空间,

%ProgramFiles%\ Microsoft ASP.NET\ASP.NET网页{VERSION}\Assemblies\System.Web.Helpers.dll

要么

%ProgramFiles(x86)%\ Microsoft ASP.NET\ASP.NET网页{VERSION}\Assemblies\System.Web.Helpers.dll

希望这可以帮助!

Answer 7

public static class Utilities
{
    public static T Deserialize<T>(string jsonString)
    {
        using (MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(jsonString)))
        {    
            DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(T));
            return (T)serializer.ReadObject(ms);
        }
    }
}

更多信息,请访问以下链接 http://ishareidea.blogspot.in/2012/05/json-conversion.html

关于DataContractJsonSerializer Class你可以在这里阅读.

Answer 8

使用JavaScriptSerializer()不如提供的通用解决方案严格:public static T Deserialize(string json)

将json传递给与您尝试转换为的Object定义不完全匹配的服务器时,这可能会派上用场.