Oracle：在函数中返回多行

Question

我正在尝试创建一个返回多行的函数。

以下是我的功能和类型

create or replace type emp_type
(
first_name varchar2(20)
, last_name varchar2(20)
, depart_name varchar2(20)
)
/
create or replace function get_employee
 (loc in number)
return emp_type
as  
   emp_record emp_type;
begin
    select a.first_name, a.last_name, b.department_name into emp_record.first_name,
emp_record.last_name,emp_record.depart_name 
   from employees a, departments b 
    where a.department_id=b.department_id and location_id=loc;

   return(emp_record);  
end;

我用过

select get_employee(5) from dual;

我收到“ exact fetch returns more than requested number of rows”错误。后来当我rownum<2在选择查询中使用时，我得到了“ Reference to uninitialized composite”。

能否请你帮忙？

提前致谢

Answer 1

如果要返回 a sys_refcursor，则没有理由声明对象类型或尝试返回对象类型。只需返回一个sys_refcursor.

create or replace function get_employee
  (p_loc in number)
  return sys_refcursor
as  
  l_rc sys_refcursor;
begin
  open l_rc
   for select a.first_name, a.last_name, b.department_name 
         from employees a, 
              departments b 
        where a.department_id=b.department_id 
          and location_id=p_loc;

  return l_rc; 
end;