Bar*_*Bar 1 cocoa-touch objective-c nsmutablearray nsarray ios
我有这样的数组
A = [@"aa",@"cc",@"bb",@"bb",@"cc",@"aa",@"cc"]
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我需要将其转换为
A = [@"x2 aa",@"x2 bb",@"x3 cc"]
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计算相似的元素并创建一个新字符串,将其添加到新数组中.如下图所示:
NSArray *aArray = @[@"aa", @"cc", @"bb", @"bb", @"cc", @"aa", @"cc"];
NSCountedSet *set = [NSCountedSet setWithArray:aArray];
NSMutableArray *countedArray = [NSMutableArray new];
for (NSString *str in set) {
[countedArray addObject:[NSString stringWithFormat:@"x%ld %@",[set countForObject:str], str]];
}
NSLog(@"%@",countedArray);
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输出:
("x2 bb","x2 aa","x3 cc")
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