SQL Server,将持续时间行拆分24小时

Question

我正在使用sql server 2008 r2.我试图在FromDate,Todate之间分配24小时的时间段.例如,如果时间行给出如下,(FromDate,Todate之间的范围是4天,所以我想要4行)

ID   FromDate                 Todate     
---- ------------------------ -------------------------
1    2014-04-01 08:00:00.000  2014-04-04 12:00:00.000

结果我想看到这样的结果:

ID   FromDate                 Todate                   DateDiff(HH)
---- ------------------------ -----------------------------------
1    2014-04-01 08:00:00.000  2014-04-01 23:59:59.000  15
1    2014-04-02 00:00:00.000  2014-04-02 23:59:59.000  23
1    2014-04-03 00:00:00.000  2014-04-03 23:59:59.000  23
1    2014-04-04 00:00:00.000  2014-04-04 12:00:00.000  12

Answer 1

试试这个查询:

WITH TAB1 (ID,FROMDATE,TODATE1,TODATE) AS
(SELECT ID,
FROMDATE,
DATEADD(SECOND, 24*60*60 - 1, CAST(CAST(FROMDATE AS DATE) AS DATETIME)) TODATE1,
TODATE 
FROM TABLE1
UNION ALL
SELECT 
ID,
DATEADD(HOUR, 24, CAST(CAST(TODATE1 AS DATE) AS DATETIME)) FROMDATE,
DATEADD(SECOND, 2*24*60*60-1, CAST(CAST(TODATE1 AS DATE) AS DATETIME)) TODATE1,
TODATE
FROM TAB1 WHERE CAST(TODATE1 AS DATE) < CAST(TODATE AS DATE)
),
TAB2 AS
(SELECT ID,FROMDATE,
CASE WHEN TODATE1 > TODATE THEN TODATE ELSE TODATE1 END AS TODATE
FROM TAB1)
SELECT TAB2.*,
DATEPART(hh, TODATE) - DATEPART(hh, FROMDATE) [DateDiff(HH)] FROM TAB2;

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