在C#中将换行符添加到字符串中

Question

我有一个字符串.

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";

我需要在字符串中每次出现"@"符号后添加换行符.

我的输出应该是这样的

fkdfdsfdflkdkfk@
dfsdfjk72388389@
kdkfkdfkkl@
jkdjkfjd@
jjjk@

Answer 1

string text = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";

text = text.Replace("@", "@" + System.Environment.NewLine);

Answer 2

你可以在@符号之后添加一个换行符,如下所示:

string newString = oldString.Replace("@", "@\n");  

您还可以NewLine在Environment类中使用该属性(我认为它是环境).

Answer 3

之前的答案很接近,但为了满足@符号保持接近的实际要求,您需要这样做str.Replace("@", "@" + System.Environment.NewLine).这将保留@符号并为当前平台添加适当的换行符.

Answer 4

然后只需修改以前的答案:

Console.Write(strToProcess.Replace("@", "@" + Environment.NewLine));

如果您不想在文本文件中添加换行符,则不要保留它.

Answer 5

一个简单的字符串替换将完成这项工作.看看下面的示例程序:

using System;

namespace NewLineThingy
{
    class Program
    {
        static void Main(string[] args)
        {
            string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
            str = str.Replace("@", "@" + Environment.NewLine);
            Console.WriteLine(str);
            Console.ReadKey();
        }
    }
}

Answer 6

正如其他人所说的那样,新行char会在windows中的文本文件中为你提供一个新行.尝试以下方法:

using System;
using System.IO;

static class Program
{
    static void Main()
    {
        WriteToFile
        (
        @"C:\test.txt",
        "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@",
        "@"
        );

        /*
        output in test.txt in windows =
        fkdfdsfdflkdkfk@
        dfsdfjk72388389@
        kdkfkdfkkl@
        jkdjkfjd@
        jjjk@ 
        */
    }

    public static void WriteToFile(string filename, string text, string newLineDelim)
    {
        bool equal = Environment.NewLine == "\r\n";

        //Environment.NewLine == \r\n = True
        Console.WriteLine("Environment.NewLine == \\r\\n = {0}", equal);

        //replace newLineDelim with newLineDelim + a new line
        //trim to get rid of any new lines chars at the end of the file
        string filetext = text.Replace(newLineDelim, newLineDelim + Environment.NewLine).Trim();

        using (StreamWriter sw = new StreamWriter(File.OpenWrite(filename)))
        {
            sw.Write(filetext);
        }
    }
}

Answer 7

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
var result = strToProcess.Replace("@", "@ \r\n");
Console.WriteLine(result);

输出