Kou*_*siK 2 android android-listview
我正在尝试将自定义选择器设置为ListView.它在较新的设备上工作正常,但不能在较低版本的设备上工作.我希望ListView所选项目保持突出显示.
请帮忙.
提前致谢.
ListView.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<ListView
android:id="@+id/listViewBell"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:cacheColorHint="#00000000"
android:choiceMode="singleChoice"
android:divider="#b5b5b5"
android:dividerHeight="1dp"
android:listSelector="@drawable/list_selector_color" >
</ListView>
</LinearLayout>
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list_selectror_color.xml
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle" >
<solid android:color="@color/list_selector" />
<stroke
android:dashWidth="2dp"
android:width="1dp"
android:color="@color/white" />
</shape>
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我也尝试过选择器,但没有任何反应
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="@drawable/list_selector_color" android:state_pressed="true"/>
<item android:drawable="@drawable/list_selector_color" android:state_focused="true"/>
<item android:drawable="@drawable/list_selector_color" android:state_selected="true"/>
<item android:drawable="@drawable/list_selector_normal"/>
</selector>
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这是我的自定义适配器getView方法
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) mContext
.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = inflater.inflate(R.layout.listview_bell_items, parent,
false);
ImageView imageview = (ImageView) convertView
.findViewById(R.id.list_bell_image);
imageview.setImageResource(mDataImage[position]);
TextView textview = (TextView) convertView
.findViewById(R.id.txt_bell_title);
textview.setText(mDataText[position]);
return convertView;
}
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Dre*_*rew 22
我有类似的问题.对不起,无法发表评论,所以我发布了一个可能的答案.
android:listSelector="@drawable/list_selector_color"从ListView声明中删除属性
在R.layout.listview_bell_items为根布局指定自定义选择器.例如,如果列表项的根布局是RelativeLayout,请尝试:
<RelativeLayout ... android:background="@drawable/listitem_selector">...
任何其他类型的布局也是如此.
如果仍然无法提供您想要的结果,请提供更多详细信息.
更新 确定,如果没有其他帮助,那么您的问题就会出现临时的脏问题.我不明白为什么它不起作用.
引入一个包含当前所选项的selectedPos变量.
private class MyAdapter extends .../*your base adapter*/ {
private static final int NOT_SELECTED = -1;
private int selectedPos = NOT_SELECTED;
// if called with the same position multiple lines it works as toggle
public void setSelection(int position) {
if (selectedPos == position) {
selectedPos = NOT_SELECTED;
} else {
selectedPos = position;
}
notifyDataSetChanged();
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View view = super.getView(position, convertView, parent);
if (position == selectedPos) {
// your color for selected item
view.setBackgroundColor(Color.parseColor("#000000"));
} else {
// your color for non-selected item
view.setBackgroundColor(Color.parseColor("#FFFFFF"));
}
return view;
}
}
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现在,在创建并设置ListView适配器后添加以下代码:
final MyAdapter adapter = new MyAdapter(...);
listView.setAdapter(adapter);
listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
adapter.setSelection(position);
}
});
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