我是新来的Android,我真的需要做这种方式(我认为是另一个这样做Activity),但任何人都可以告诉我一个简单的代码(只是onCreate()可以做法)Listview没有ListActivity?
谢谢
Pat*_*fka 55
如果你有一个活动的xml布局,包括像这样的listView
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent">
<ListView android:id="@android:id/list"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:layout_weight="fill_parent"
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然后在你的onCreate你可以有这样的东西
setContentView(R.layout.the_view);
ArrayAdapter<String> adapter = new ArrayAdapter<>(this, android.R.layout.simple_list_item_1, myList);
ListView lv = (ListView)findViewById(android.R.id.list);
lv.setAdapter(adapter);
lv.setOnItemClickListener(new OnItemClickListener()
{
@Override
public void onItemClick(AdapterView<?> a, View v,int position, long id)
{
Toast.makeText(getBaseContext(), "Click", Toast.LENGTH_LONG).show();
}
});
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evi*_*ate 28
在res/layout/main.xml文件中包含以下资源:
<ListView
android:id="@+id/id_list_view"
android:layout_width="fill_parent"
android:layout_height="fill_parent" />
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your_class.java
import android.widget.ListView;
import android.widget.ArrayAdapter;
public class your_class extends Activity
{
private ListView m_listview;
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
m_listview = (ListView) findViewById(R.id.id_list_view);
String[] items = new String[] {"Item 1", "Item 2", "Item 3"};
ArrayAdapter<String> adapter =
new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, items);
m_listview.setAdapter(adapter);
}
}
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cch*_*son 11
下面以编程方式创建一个简单的ListView:
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
String[] myList = new String[] {"Hello","World","Foo","Bar"};
ListView lv = new ListView(this);
lv.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,myList));
setContentView(lv);
}
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