可以通过Django的管理员监控django_admin_log吗？

Question

该表django_admin_log可用于监视管理员中用户的操作.现在,我可以通过直接查询数据库来实现这一目标.是否有内置功能,我可以django_admin_log通过Django的管理员查看所有用户的表格？

Answer 1

你不能只:

from django.contrib.admin.models import LogEntry
admin.site.register(LogEntry)

在你的一个admin.py文件中？我只是测试它,它是准系统,但它的工作原理.

您可能希望更具体,并ModelAdmin为LogEntry 创建一个类,以提供更好的列表视图和一些过滤功能.但这应该有效.

Answer 2

这是我的版本. 可用字段的参考.

class LogAdmin(admin.ModelAdmin):
    """Create an admin view of the history/log table"""
    list_display = ('action_time','user','content_type','change_message','is_addition','is_change','is_deletion')
    list_filter = ['action_time','user','content_type']
    ordering = ('-action_time',)
    #We don't want people changing this historical record:
    def has_add_permission(self, request):
        return False
    def has_change_permission(self, request, obj=None):
        #returning false causes table to not show up in admin page :-(
        #I guess we have to allow changing for now
        return True
    def has_delete_permission(self, request, obj=None):
        return False

Answer 3

这是一个更广泛的管理配置，用于查看依赖 Django 2.1 仅查看权限的所有日志条目：

from django.contrib import admin
from django.contrib.admin.models import LogEntry, DELETION
from django.utils.html import escape
from django.utils.safestring import mark_safe
from django.urls import reverse

@admin.register(LogEntry)
class LogEntryAdmin(admin.ModelAdmin):
    date_hierarchy = 'action_time'
    readonly_fields = ('action_time',)
    list_filter = ['user', 'content_type']
    search_fields = ['object_repr', 'change_message']
    list_display = ['__str__', 'content_type', 'action_time', 'user', 'object_link']

    # keep only view permission
    def has_add_permission(self, request):
        return False

    def has_change_permission(self, request, obj=None):
        return False

    def has_delete_permission(self, request, obj=None):
        return False

    def object_link(self, obj):
        if obj.action_flag == DELETION:
            link = obj.object_repr
        else:
            ct = obj.content_type
            try:
                link = mark_safe('<a href="%s">%s</a>' % (
                                 reverse('admin:%s_%s_change' % (ct.app_label, ct.model),
                                         args=[obj.object_id]),
                                 escape(obj.object_repr),
                ))
            except NoReverseMatch:
                link = obj.object_repr
        return link
    object_link.admin_order_field = 'object_repr'
    object_link.short_description = 'object'

    def queryset(self, request):
        return super(LogEntryAdmin, self).queryset(request) \
            .prefetch_related('content_type')

它基于此 Django 代码段，结果如下所示：

如果您想将它与较早的 Django 版本一起使用，请参阅此答案的较早版本。