C#File.ReadallText做了奇怪的事情

Question

我正在尝试做的是读取文件中的所有文本,如果它包含单词"共享"做一个正则表达式.这是代码:

DirectoryInfo dinfo = new DirectoryInfo(@"C:\Documents and Settings\g\Desktop\123");
        FileInfo[] Files = dinfo.GetFiles("*.txt");
        foreach (FileInfo filex in Files)
        {
            string contents = File.ReadAllText(filex.FullName);
            string matchingcontants = "Share";
            if (contents.Contains(matchingcontants))
            {
                string sharename = Regex.Match(contents, @"\+(\S*)(.)(.*)(.)").Groups[3].Value;
                File.AppendAllText(@"C:\sharename.txt", sharename + @"\r\n");
            }

        }

当我调试时,我得到...... contents ="\ r\0 \n\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0 =\0\r\0 \n\0 +\0S\0h\0a\0r\0e\0\0 \\ 0 \\ 0j\05\02\0 \\ 0w\0w\0w\0_\0O\0N \0吨\

\ 0S\0H\0A\0R\0E \

不共享.任何提示？提示或建议？

Answer 1

看起来你有一个保存为UTF-16(即Encoding.Unicode)的文件.使用正确的编码读取文件,一切都应该很好.

幸运的是,File.ReadAllText的重载采用了编码:

string contents = File.ReadAllText(filex.FullName, Encoding.Unicode);

不幸的是,对于不是 UTF-16的文件,这将是错误的.虽然存在猜测编码的启发式方法,但理想情况下,您应该在打开文件之前知道编码.