use*_*864 7 python windows exe py2exe
我正在使用Py2exe从我的Python脚本创建一个Windows .exe.我想拥有版权信息以及产品版本,描述等.我已经能够显示所有内容(在属性> exe的详细信息中),版权信息除外.我试过以下但没有成功:
from distutils.core import setup
import py2exe
import sys
if len(sys.argv) == 1:
sys.argv.append("py2exe")
sys.argv.append("-q")
class Target:
def __init__(self, **kw):
self.__dict__.update(kw)
# for the versioninfo resources
self.version = "1.0.0.0"
self.company_name = "ACME."
self.copyright = "Copyright (c) 2014 ACME."
self.name = "My Program"
# create an instance of class Target
# and give it additional needed info
target = Target(
description = "Test Description",
# this is your code file
script = "Main.py",
# this will form TestProgram.exe
dest_base = "TestProgram")
setup(
options = {'py2exe': {'bundle_files': 1,
'compressed': 1}},
console = [{'script': "Main.py"}],
zipfile = None,
)
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使用此方法时,我在.exe的PROPERTIES> DETAILS中获取文件描述,产品名称和产品版本,但我没有版权.
我得到以下工作.我意识到我没有把目标设定为正确.固定在我做的底部console = [target].
from distutils.core import setup
import py2exe
import sys
if len(sys.argv) == 1:
sys.argv.append("py2exe")
sys.argv.append("-q")
class Target:
def __init__(self, **kw):
self.__dict__.update(kw)
self.version = "1.0.0.0"
self.company_name = "ACME."
self.copyright = "Copyright (c) 2014 ACME."
self.name = "My Program"
target = Target(
description = "Test Description",
script = "Main.py",
dest_base = "TestProgram")
setup(
options = {'py2exe': {'bundle_files': 1,
'compressed': True}},
zipfile = None,
console = [target]
)
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我认为您的代码确实有问题,因为它没有更新 exe 中的文件描述、产品名称和产品版本。然而,这段代码确实:
from distutils.core import setup
import py2exe
setup(
options = {'py2exe': {'bundle_files': 1,
'compressed': 1}},
console = [{'script': "Main.py"}],
zipfile = None,
version = "1.0.0.0",
name = "My Program",
description = "Test Description",
)
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将公司名称和版权信息放入可执行文件更具挑战性,不幸的是,我还不知道该怎么做。 这可能有用。
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