如何获取烧瓶中get请求的参数值？

Question

我在网上找到的答案是使用request.args.get.但是,我无法管理它.我有以下简单示例:

from flask import Flask
app = Flask(__name__)

@app.route("/hello")
def hello():
    print request.args['x']
    return "Hello World!"

if __name__ == "__main__":
    app.run()

我进入127.0.0.1:5000/hello?x=2浏览器,结果得到:

Internal Server Error

The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the application.

我究竟做错了什么？

Answer 1

简单的答案是您没有request从flask包中导入全局对象.

from flask import Flask, request

通过执行调试模式运行开发服务器,可以很容易地确定自己

app.run(debug=True)

这将为您提供一个堆栈跟踪,包括:

print request.args['x']
NameError: global name 'request' is not defined

Answer 2

http:// localhost:5000/api/iterators/opel/next ？n = 5

对于类似之前的情况

from flask import Flask, request
n = request.args.get("n")

可以做到这一点