Ret*_*dor 2 html javascript css colors
我正在一个工作委员会工作,其中有大量不断变化的职位发布.但是每个职位发布都应该有一种基色的分层色调:#219BBE.这是我想要实现的目标的草图:

我需要的是一个javascript函数,它根据job_boxes 的数量改变颜色的阴影.
到目前为止,我发现了一个用于生成阴影的javascript片段#219BBE.
function calculateShades(colorValue) {
"#219BBE" = colorValue;
// break the hexadecimal color value into R, G, B one-byte components
// and parse into decimal values.
// calculate a decrement value for R, G, and B based on 10% of their
// original values.
var red = parseInt(colorValue.substr(0, 2), 16);
var redDecrement = Math.round(red*0.1);
var green = parseInt(colorValue.substr(2, 2), 16);
var greenDecrement = Math.round(green*0.1);
var blue = parseInt(colorValue.substr(4, 2), 16);
var blueDecrement = Math.round(blue*0.1);
var shadeValues = [];
var redString = null;
var greenString = null;
var blueString = null;
for (var i = 0; i < 10; i++) {
redString = red.toString(16); // convert red to hexadecimal string
redString = pad(redString, 2); // pad the string if needed
greenString = green.toString(16); // convert green to hexadecimal string
greenString = pad(greenString, 2); // pad the string if needed
blueString = blue.toString(16); // convert blue to hexadecimal string
blueString = pad(blueString, 2); // pad the string if needed
shadeValues[i] = redString + greenString + blueString;
// reduce the shade towards black
red = red - redDecrement;
if (red <= 0) {
red = 0;
}
green = green - greenDecrement;
if (green <= 0) {
green = 0;
}
blue = blue - blueDecrement;
if (blue <= 0) {
blue = 0;
}
}
shadeValues[10] = "000000";
return shadeValues;
}
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我简化了这个问题的输出: HTML
<!-- Instead of 4 boxes we could also have n boxes -->
<div class="job_box"></div>
<div class="job_box"></div>
<div class="job_box"></div>
<div class="job_box"></div>
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CSS
.job_box {
width: 100%;
height: 50px;
/* The dynamic background-color */
background-color: #219BBE;
}
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要计算job_boxes 的数量,我将使用jQuery:
var numBoxes = $('.job_box').length
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这就是我被卡住的地方.我知道我需要一个循环,但就是这样.你能帮助我朝正确的方向发展吗?
这是我的解决方案:DEMO
var n = 0;
$('.job_box').each(function() {
n++;
lighten($(this), n);
});
function lighten(that, n) {
var lightenPercent = 15 / n;
var rgb = that.css('background-color');
rgb = rgb.replace('rgb(', '').replace(')', '').split(',');
var red = $.trim(rgb[0]);
var green = $.trim(rgb[1]);
var blue = $.trim(rgb[2]);
red = parseInt(red * (100 - lightenPercent) / 100);
green = parseInt(green * (100 - lightenPercent) / 100);
blue = parseInt(blue * (100 - lightenPercent) / 100);
rgb = 'rgb(' + red + ', ' + green + ', ' + blue + ')';
that.css('background-color', rgb);
}
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您可以在另一方面,通过改变变暗你的基本色/,以*设定的百分比时变种.