我想从IMAP4服务器获取整个消息.在python docs中,如果发现这段代码有效:
>>> t, data = M.fetch('1', '(RFC822)')
>>> body = data[0][1]
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我想知道我是否总能相信数据[0] [1]返回消息正文.当我运行'RFC822.SIZE'时,我只有一个字符串而不是一个元组.
我已经浏览了rfc1730,但我无法找出'RFC822'的正确响应结构.从imaplib文档中判断获取结果结构也很困难.
这是我在获取时获得的内容RFC822:
('OK', [('1 (RFC822 {858569}', 'body of the message', ')')])
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但当RFC822.SIZE我拿到我的时候:
('OK', ['1 (RFC822.SIZE 847403)'])
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我该如何正确处理数据[0]列表?我可以相信,当它是一个元组列表时,元组恰好有3个部分而第二部分是有效负载吗?
也许你知道imap4的更好的库?
Mat*_*ttH 30
不...... imaplib是一个非常好的图书馆,它是如此难以理解的imap.
您可能希望检查一下t == 'OK',但data[0][1]按照我的预期使用它.
这是我用来提取我通过电子邮件收到的签名证书的快速示例,而不是防弹,但适合我的目的:
import getpass, os, imaplib, email
from OpenSSL.crypto import load_certificate, FILETYPE_PEM
def getMsgs(servername="myimapserverfqdn"):
usernm = getpass.getuser()
passwd = getpass.getpass()
subject = 'Your SSL Certificate'
conn = imaplib.IMAP4_SSL(servername)
conn.login(usernm,passwd)
conn.select('Inbox')
typ, data = conn.search(None,'(UNSEEN SUBJECT "%s")' % subject)
for num in data[0].split():
typ, data = conn.fetch(num,'(RFC822)')
msg = email.message_from_string(data[0][1])
typ, data = conn.store(num,'-FLAGS','\\Seen')
yield msg
def getAttachment(msg,check):
for part in msg.walk():
if part.get_content_type() == 'application/octet-stream':
if check(part.get_filename()):
return part.get_payload(decode=1)
if __name__ == '__main__':
for msg in getMsgs():
payload = getAttachment(msg,lambda x: x.endswith('.pem'))
if not payload:
continue
try:
cert = load_certificate(FILETYPE_PEM,payload)
except:
cert = None
if cert:
cn = cert.get_subject().commonName
filename = "%s.pem" % cn
if not os.path.exists(filename):
open(filename,'w').write(payload)
print "Writing to %s" % filename
else:
print "%s already exists" % filename
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试试我的包:https : //pypi.org/project/imap-tools/
例子:
from imap_tools import MailBox
# get list of email bodies from INBOX folder
with MailBox('imap.mail.com').login('test@mail.com', 'password', 'INBOX') as mailbox:
bodies = [msg.text or msg.html for msg in mailbox.fetch()]
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