从 SQLAlchemy 结果返回字段名称和值

Question

如何使用 sqlalchemy 获取表列名和值？

使用我所拥有的，我可以检索：

(2, 'blue', 'square')

但我想得到的是：

{'id': 2, 'color': 'blue', 'type': 'square'}

波纹管，我在阅读0.9 版文档后写的内容：

连接管理器.py

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import sqlalchemy
from sqlalchemy import Table, MetaData
from sqlalchemy.orm import sessionmaker
from sqlalchemy.ext.declarative import declarative_base


location = 'localhost'
engine_str = 'mysql+mysqlconnector://xx:xx@{}/xx'.format(location)
engine = sqlalchemy.create_engine(engine_str, echo=False)
session = sessionmaker(bind=engine)
connection = engine.connect()
session = session(bind=connection)
metadata = MetaData()
Base = declarative_base()

class SelectType(object):
    """
    Server's details on database
    """
    def go(self, s, cc, pp):
        __table__ = Table('servers', metadata, autoload=True, autoload_with=engine)
        result = s.query(__table__).filter_by(color=cc).filter_by(type=pp).all()
        return result

def select_type(e, p):
    """
    return SelectType result
    """
    try:
        return SelectType().go(session, e, p)
    except:
        raise
    finally:
        session.close()

主文件.py

#!/usr/bin/env python
# -*- coding: utf-8 -*-
from resources import connection_manager

if __name__ == "__main__":
    try:
for i in connection_manager.select_type('blue', 'square'):
    print(i)

重要的是要注意我正在使用自动加载

Answer 1

使用Query.column_descriptions这里你去：

class SelectType(object):
    def go(self, s, cc, pp):
        __table__ = Table('servers', metadata, autoload=True, autoload_with=engine)
        result = s.query(__table__).filter_by(color=environment).filter_by(type=pp)
        column_names = [c["name"] for c in result.column_descriptions]
        return [dict(zip(column_names, row)) for row in result.all()]