如何使用对象ID数组创建Mongoose模式？

Question

我已经定义了一个mongoose用户架构:

var userSchema = mongoose.Schema({
  email: { type: String, required: true, unique: true},
  password: { type: String, required: true},
  name: {
      first: { type: String, required: true, trim: true},
      last: { type: String, required: true, trim: true}
  },
  phone: Number,
  lists: [listSchema],
  friends: [mongoose.Types.ObjectId],
  accessToken: { type: String } // Used for Remember Me
});

var listSchema = new mongoose.Schema({
    name: String,
    description: String,
    contents: [contentSchema],
    created: {type: Date, default:Date.now}
});
var contentSchema = new mongoose.Schema({
    name: String,
    quantity: String,
    complete: Boolean
});

exports.User = mongoose.model('User', userSchema);

friends参数定义为Object ID数组.换句话说,用户将拥有一个包含其他用户ID的数组.我不确定这是否是这样做的正确表示法.

我正在尝试将新朋友推送到当前用户的朋友数组:

user = req.user;
  console.log("adding friend to db");
  models.User.findOne({'email': req.params.email}, '_id', function(err, newFriend){
    models.User.findOne({'_id': user._id}, function(err, user){
      if (err) { return next(err); }
      user.friends.push(newFriend);
    });
  });

但是这给了我以下错误:

TypeError:对象531975a04179b4200064daf0没有方法'cast'

Answer 1

如果你想使用Mongoose populate功能,你应该这样做:

var userSchema = mongoose.Schema({
  email: { type: String, required: true, unique: true},
  password: { type: String, required: true},
  name: {
      first: { type: String, required: true, trim: true},
      last: { type: String, required: true, trim: true}
  },
  phone: Number,
  lists: [listSchema],
  friends: [{ type : ObjectId, ref: 'User' }],
  accessToken: { type: String } // Used for Remember Me
});
exports.User = mongoose.model('User', userSchema);

这样您就可以执行以下查询:

var User = schemas.User;
User
 .find()
 .populate('friends')
 .exec(...)

你会看到每个用户都有一个用户数组(这个用户的朋友).

插入的正确方法就像Gabor所说:

user.friends.push(newFriend._id);

Answer 2

我自己是Mongoose的新手,所以我不完全确定这是对的.但是,您似乎写了:

friends: [mongoose.Types.ObjectId],

我相信您正在寻找的房产实际上是在这里找到的:

friends: [mongoose.Schema.Types.ObjectId],

可能是因为你发布了这个问题后文档已经改变了.如果是这样的话,请道歉.有关更多信息和示例,请参阅Mongoose SchemaTypes文档.

Answer 3

我会尝试这个.

user.friends.push(newFriend._id);

要么

friends: [userSchema],

但我不确定这是否正确.