jBCrypt 0.3 C#Port(BCrypt.net)

Question

在查看了原始jBCrypt v0.1 C#端口中的一个错误:BCrypt.net(相关问题).我决定将新的jBCrypt代码与旧的C#端口进行比较,以查找差异和潜在问题,如相关问题的错误.

这是我发现的:

// original java (jBCrypt v0.3):
private static int streamtoword(byte data[], int offp[]) {
        int i;
        int word = 0;
        int off = offp[0];

        for (i = 0; i < 4; i++) {
            word = (word << 8) | (data[off] & 0xff);
            off = (off + 1) % data.length;
        }

        offp[0] = off;
        return word;
}


// port to C# :
private static uint StreamToWord(byte[] data, ref int offset)
{

    uint word = 0;

    for (int i = 0; i < 4; i++)
    {
        // note the difference with the omission of "& 0xff"
        word = (word << 8) | data[offset];
        offset = (offset + 1) % data.Length;
    }

    return word;
}

如果先前不正确将以下修复吗？

private static uint StreamToWord(byte[] data, ref int[] offsetp)
{

    uint word = 0;
    int offset = offsetp[0];
    for (int i = 0; i < 4; i++)
    {
        word = (word << 8) | (uint)(data[offset] & 0xff);
        offset = (offset + 1) % data.Length;
    }

    offsetp[0] = offset;

    return word;
}

Answer 1

将& 0xff在Java版本需要的,因为在Java中,字节签名.(有些人认为这是一个错误.)

在C#中,字节是无符号的,因此& 0xff不需要.