Objective-C - 如何获得Boleans的总和？

Question

通过下面的代码,我可以获得如下输出:
0
1
1

我想要的是输出这些布尔值的总和,在我的例子中,结果将是:
2因为我们有0+1+1

代码[更新]:

  -(void)markers{
        CLLocationCoordinate2D tg = CLLocationCoordinate2DMake(location.latitude, location.longitude);
        GMSCoordinateBounds *test = [[GMSCoordinateBounds alloc]initWithPath:path];
        BOOL test3 = [test containsCoordinate:tg];
        {
            if (test3 == 1)
            {
  marker.position = CLLocationCoordinate2DMake(location.latitude, location.longitude);                     
            }else if (test3 == 0)
            {
  marker.position = CLLocationCoordinate2DMake(0, 0);
            }
        }
    }       
}

Answer 1

而不是求和BOOLs,这是违反直觉的,循环使用你用于获取BOOL值的任何东西,如果你得到YES,则增加一个计数器.这将是您拥有的YES数.

如果你有一个BOOL数组,你可以只使用谓词过滤数组以获得YES值,结果数组的长度是你拥有的YES数.

编辑后在OP注释后添加代码示例

递增一个柜台

NSUInteger numberOfBools = 0;
CLLocationCoordinate2D tg = CLLocationCoordinate2DMake(location.latitude, location.longitude);
GMSCoordinateBounds *test = [[GMSCoordinateBounds alloc]initWithPath:path];
if ([test containsCoordinate:tg1]) { ++numberOfBools; }
if ([test containsCoordinate:tg2]) { ++numberOfBools: }
... // other tests here;

// numberOfBools now contains the number of passing tests.

再次编辑,添加完整代码后

// snipped code above here
// This is where you add the counter and initialise it to 0
NSUInteger numberOfBools = 0;
for (NSDictionary *dictionary in array)
{            
    // Snip more code to this point
    BOOL test3 = [test containsCoordinate:tg];
    {
        if (test3)
        {
        // This is where you increment the counter
        ++numberOfBools;

// Snip more code to the end of the for block
}

// Now numberOfBools shows how many things passed test3