无法将第二个枚举值转换为int？

Question

我不懂.我能够将我的第一个枚举值转换为int而不是第二个？

public enum PayPalTransactionType
{
    Authorization = 0, // Debit
    Capture = 1, // Credit
    Refund = 2,
    Void = 3
}

public string GetPayPalTransCode(PayPalServiceBase.PayPalTransactionType payPalTransactionType)
{
    string actionCode = string.Empty;

    switch (payPalTransactionType)
    {
        case (int)PayPalServiceBase.PayPalTransactionType.Authorization:
            actionCode = "Debit";
            break;
        case (int)PayPalServiceBase.PayPalTransactionType.Capture:
            actionCode = "Credit";
            break;
    }

    return actionCode;
}

在我的第二个案例陈述中我得到了这个投射错误:

无法隐式转换int 为PayPalTransactionType.存在显式转换(您是否错过了演员？)

Answer 1

你为什么要在第一时间施展？只要将其作为枚举值保留在各处:

public string GetPayPalTransCode
    (PayPalServiceBase.PayPalTransactionType payPalTransactionType)
{
    string actionCode = string.Empty;

    switch (payPalTransactionType)
    {
        case PayPalServiceBase.PayPalTransactionType.Authorization:
            actionCode = "Debit";
            break;
        case PayPalServiceBase.PayPalTransactionType.Capture:
            actionCode = "Credit";
            break;
    }

    return actionCode;
}

另外,我对未识别的代码有明确的默认操作,只是直接返回:

public string GetPayPalTransCode
    (PayPalServiceBase.PayPalTransactionType payPalTransactionType)
{
    switch (payPalTransactionType)
    {
        case PayPalServiceBase.PayPalTransactionType.Authorization:
            return "Debit";
        case PayPalServiceBase.PayPalTransactionType.Capture:
            return "Credit";
        default:
            return ""; // Or throw an exception if this represents an error
    }
}

或者,您可以使用Dictionary<PayPalTransactionType, string>.

Answer 2

你为什么要投掷int？你正在做的事情switch已经是enum类型了!