我在python中使用try except block,而try块失败,如何打印有意义的错误消息.我在C中寻找类似perror()的东西
>>> try:
... 0/0
... except Exception,e:
... print e.message
...
integer division or modulo by zero
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或者在Python 2.6及以上版本中e.args,因为BaseException.message has been deprecated
>>> try:
... 0/0
... except Exception,e:
... print e.args
...
('integer division or modulo by zero',)
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