来自python的诞生日期

Question

我怎样才能从今天的日期和一个人的出生日期中找到蟒蛇的年龄？birthdate来自Django模型中的DateField.

Answer 1

考虑到int(True)为1且int(False)为0,可以做得更简单:

from datetime import date

def calculate_age(born):
    today = date.today()
    return today.year - born.year - ((today.month, today.day) < (born.month, born.day))

Answer 2

from datetime import date

def calculate_age(born):
    today = date.today()
    try: 
        birthday = born.replace(year=today.year)
    except ValueError: # raised when birth date is February 29 and the current year is not a leap year
        birthday = born.replace(year=today.year, month=born.month+1, day=1)
    if birthday > today:
        return today.year - born.year - 1
    else:
        return today.year - born.year

更新:使用Danny的解决方案,它会更好

Answer 3

from datetime import date

days_in_year = 365.2425    
age = int((date.today() - birth_date).days / days_in_year)

在Python 3中,您可以执行除法datetime.timedelta:

from datetime import date, timedelta

age = (date.today() - birth_date) // timedelta(days=365.2425)

Answer 4

正如@ [Tomasz Zielinski]和@Williams所建议的那样,python-dateutil只能做5行.

from dateutil.relativedelta import *
from datetime import date
today = date.today()
dob = date(1982, 7, 5)
age = relativedelta(today, dob)

>>relativedelta(years=+33, months=+11, days=+16)`

Answer 5

最简单的方法是使用 python-dateutil

import datetime

import dateutil

def birthday(date):
    # Get the current date
    now = datetime.datetime.utcnow()
    now = now.date()

    # Get the difference between the current date and the birthday
    age = dateutil.relativedelta.relativedelta(now, date)
    age = age.years

    return age

Answer 6

from datetime import date

def age(birth_date):
    today = date.today()
    y = today.year - birth_date.year
    if today.month < birth_date.month or today.month == birth_date.month and today.day < birth_date.day:
        y -= 1
    return y

Answer 7

不幸的是,你不能只使用timedelata作为它使用的最大单位是日和闰年将使你的计算无效.因此,如果去年未满,我们可以找到年数,然后调整一年:

from datetime import date
birth_date = date(1980, 5, 26)
years = date.today().year - birth_date.year
if (datetime.now() - birth_date.replace(year=datetime.now().year)).days >= 0:
    age = years
else:
    age = years - 1

UPD:

当2月29日发挥作用时,这个解决方案确实会导致异常.这是正确的检查:

from datetime import date
birth_date = date(1980, 5, 26)
today = date.today()
years = today.year - birth_date.year
if all((x >= y) for x,y in zip(today.timetuple(), birth_date.timetuple()):
   age = years
else:
   age = years - 1

UPD2:

多次调用now()性能命中是荒谬的,除了非常特殊的情况外,它并不重要.使用变量的真正原因是数据不完整的风险.

Answer 8

如果您想使用 django 模板在页面中打印此内容，那么以下内容可能就足够了：

{{ birth_date|timesince }}