Ven*_*ata 31 javascript jquery daterangepicker momentjs
我搜索了这个问题,发现Stackoverflow上没有答案..所以我决定回答它......
如果您需要将星期一作为周开始的下一个/上周的开始/结束,这个问题会有所帮助.
Dr.*_*ula 138
派对有点晚,但这是我发现表达周的开始/结束的最简单的方法.isoWeek根据ISO 8601,该论点在周一开始几周,而根据您的语言环境week开始几周(因此可能是周日或周一).
本星期:
moment().startOf('isoWeek')
moment().endOf('isoWeek')
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下周:
moment().add(1, 'weeks').startOf('isoWeek')
moment().add(1, 'weeks').endOf('isoWeek')
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上个星期:
moment().subtract(1, 'weeks').startOf('isoWeek')
moment().subtract(1, 'weeks').endOf('isoWeek')
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我喜欢这些结构,因为它们非常易读.它也很容易回去或通过指定要在多少个星期提出任何数周subtract或add.
Ven*_*ata 13
我用了这个时刻js ...你可以从这里得到它
/*
all functions return moment() object.. <br>
GetNextWeekStart().format('DD/MM/YYYY') to get 24/02/2014
*/
function GetNextWeekStart() {
var today = moment();
//edited part
var daystoMonday = 0 - (today.isoWeekday() - 1) + 7;
var nextMonday = today.subtract('days', daystoMonday);
return nextMonday;
}
function GetNextWeekEnd() {
var nextMonday = GetNextWeekStart();
var nextSunday = nextMonday.add('days', 6);
return nextSunday;
}
function GetLastWeekStart() {
var today = moment();
var daystoLastMonday = 0 - (1 - today.isoWeekday()) + 7;
var lastMonday = today.subtract('days', daystoLastMonday);
return lastMonday;
}
function GetLastWeekEnd() {
var lastMonday = GetLastWeekStart();
var lastSunday = lastMonday.add('days', 6);
return lastSunday;
}
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这是在lang文件中指定的,您可以包含lang/en-au.js或lang/en-gb.js文件并设置所需的语言标准.假设你在英国:
moment.lang('en-gb');
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如果您不想使用自定义语言,可以将其更改为默认的美国语言环境:
moment.lang('en-custom', {
week: {
dow: 1,
doy: 6 // Adjust the first week of the year, depends on the country. For the US it's 6. For the UK, 4.
}
});
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然后你可以这样做:
var date = '2014-03-24';
console.log('next start', moment(date).weekday(7).format('DD/MM/YYYY'));
console.log('next end', moment(date).weekday(13).format('DD/MM/YYYY'));
console.log('prev start', moment(date).weekday(-7).format('DD/MM/YYYY'));
console.log('prev end', moment(date).weekday(-1).format('DD/MM/YYYY'));
console.log('current start', moment(date).weekday(0).format('DD/MM/YYYY'));
console.log('current end', moment(date).weekday(6).format('DD/MM/YYYY'));
/*
next start 31/03/2014
next end 06/04/2014
prev start 17/03/2014
prev end 23/03/2014
current start 24/03/2014
current end 30/03/2014
*/
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