HP.*_*HP. 16 html javascript css angularjs
transform当它在里面时我无法上班ng-style.
<!DOCTYPE html>
<html ng-app="plunker">
<head>
<meta charset="utf-8" />
<title>AngularJS Plunker</title>
<script>document.write('<base href="' + document.location + '" />');</script>
<link rel="stylesheet" href="style.css" />
<script data-require="angular.js@1.2.x" src="http://code.angularjs.org/1.2.13/angular.js" data-semver="1.2.13"></script>
<script src="app.js"></script>
</head>
<body ng-controller="MainCtrl">
<div style="transform: rotate(3deg);-webkit-transform: rotate(3deg);-ms-transform: rotate(3deg)">Test</div>
<div ng-style="{"transform": "rotate({{number}}deg)", "-webkit-transform": "rotate({{number}}deg)", "-ms-transform": "rotate({{number}}deg)"}">{{number}}</div>
<input type="number" ng-model="number" value=1>
</body>
</html>
链接:http://plnkr.co/edit/txSzAKxLDq48LVitntro?p=preview
如果我改变input数字,顶部div应该改变并同时旋转.当它的值为3时,它应该看起来像上面的单词Test.
那么如何transform在这种情况下开始工作？
谢谢.
Cod*_*gue 38
您不能在属性内的JS字符串中使用大括号绑定.您可以将变量附加到字符串上:
<div ng-style="{'transform': 'rotate('+number+'deg)', '-webkit-transform': 'rotate('+number+'deg)', '-ms-transform': 'rotate('+number+'deg)'}">{{number}}</div>
另外,我用单打替换你的双引号.
但是,您可以考虑向控制器添加一个函数以返回适当的样式:
控制器:
// Create a variable to store the transform value
$scope.transform = "rotate(0deg)";
// When the number changes, update the transform string
$scope.$watch("number", function(val) {
$scope.transform = "rotate("+val+"deg)";
});
HTML:
<!-- We can now use the same value for all vendor prefixes -->
<div ng-style="{'transform': transform, '-webkit-transform': transform, '-ms-transform': transform }">{{number}}</div>