枚举字母表的最快方法

Question

我想迭代字母表,如下所示:

foreach(char c in alphabet)
{
 //do something with letter
}

一组字符是最好的方法吗？(感觉很讨厌)

编辑:度量标准是"实现最少的类型,同时仍然可读且健壮"

Answer 1

(假设ASCII等)

for (char c = 'A'; c <= 'Z'; c++)
{
    //do something with letter 
} 

或者,您可以将其拆分为提供程序并使用迭代器(如果您计划支持国际化):

public class EnglishAlphabetProvider : IAlphabetProvider
{
    public IEnumerable<char> GetAlphabet()
    {
        for (char c = 'A'; c <= 'Z'; c++)
        {
            yield return c;
        } 
    }
}

IAlphabetProvider provider = new EnglishAlphabetProvider();

foreach (char c in provider.GetAlphabet())
{
    //do something with letter 
} 

Answer 2

或者你可以做到,

string alphabet = "abcdefghijklmnopqrstuvwxyz";

foreach(char c in alphabet)
{
 //do something with letter
}

Answer 3

var alphabet = Enumerable.Range(0, 26).Select(i => Convert.ToChar('A' + i));

Answer 4

Enumerable.Range(65, 26).Select(a => new { A = (char)(a) }).ToList().ForEach(c => Console.WriteLine(c.A));