如何将flask-admin添加到蓝图中？

Question

例如:

from flask import Flask
from flask.ext.admin import Admin, BaseView, expose

class MyView(BaseView):
    @expose('/')
    def index(self):
        return self.render('index.html')

app = Flask(__name__)

admin = Admin(app)
admin.add_view(MyView(name='Hello'))

app.run()

但是,如果我需要一个名为"views.py"的新文件,我该如何将视图添加views.py到管理员？我需要使用蓝图吗？

Answer 1

对于我的项目,我实际上制作了一个支持烧瓶管理的Blueprint子类:

from flask import Blueprint
from flask_admin.contrib.sqla import ModelView
from flask_admin import Admin

class AdminBlueprint(Blueprint):
    views=None


    def __init__(self,*args, **kargs):
        self.views = []
        return super(AdminBlueprint, self).__init__('admin2', __name__,url_prefix='/admin2',static_folder='static', static_url_path='/static/admin')


    def add_view(self, view):
        self.views.append(view)

    def register(self,app, options, first_registration=False):
        admin = Admin(app, name='microblog', template_mode='adminlte')

        for v in self.views:
            admin.add_view(v)

        return super(AdminBlueprint, self).register(app, options, first_registration)

有关详细信息,您可以在此处阅读我的博客:http://blog.sadafnoor.me/blog/how-to-add-flask-admin-to-a-blueprint/

Answer 2

我对这个问题很晚了，但无论如何......我的猜测是你想使用应用程序工厂模式并使用 Flask-Admin。关于潜在问题有一个很好的讨论。我使用了一个非常丑陋的解决方案，在init .py 文件中实例化 Flask-Admin ：

from flask_admin.contrib.sqla import ModelView

class UserModelView(ModelView):

    create_modal = True
    edit_modal = True
    can_export = True

def create_app(config_name):
    app = Flask(__name__)
    app.config.from_object(config[config_name])
    db.init_app(app)


    # import models here because otherwise it will throw errors    
    from models import User, Sector, Article

    admin.init_app(app)
    admin.add_view(UserModelView(User, db.session))      

    # attach blueprints
    from .main import main as main_blueprint
    app.register_blueprint(main_blueprint)

    from .auth import auth as auth_blueprint
    app.register_blueprint(auth_blueprint, url_prefix='/auth')

    return app

Answer 3

您不需要为此的蓝图。在views.py增加进口的admin，你在你的主要项目中定义的对象：

from projectmodule import admin
from flask.ext.admin import BaseView, expose

class MyView(BaseView):
    @expose('/')
    def index(self):
        return self.render('index.html')

admin.add_view(MyView(name='Hello'))

并在您的主projectmodule文件中使用：

from flask import Flask
from flask.ext.admin import Admin


app = Flask(__name__)
admin = Admin(app)

# import the views
import views

app.run()

例如，您import views 在设置的行之后添加admin = Admin(app)。