Kri*_*sen 18 c# json dictionary dynamic json.net
我有一个看起来像这样的动态对象,
{
"2" : "foo",
"5" : "bar",
"8" : "foobar"
}
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我该如何将其转换为dictionary?
ann*_*ijn 31
您可以使用a RouteValueDictionary将C#对象转换为字典.请参阅:RouteValueDictionary类 - MSDN.它将object属性转换为键值对.
像这样使用它:
var toBeConverted = new {
foo = 2,
bar = 5,
foobar = 8
};
var result = new RouteValueDictionary(toBeConverted);
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Bri*_*ers 22
如果你所评论的动态值是通过你在评论中提到的Json.Net反序列化创建的,那么它应该是一个JObject.事实证明它JObject已经实现了IDictionary<string, JToken>,所以你可以将它用作没有任何转换的字典,如下所示:
string json =
@"{ ""blah"" : { ""2"" : ""foo"", ""5"" : ""bar"", ""8"" : ""foobar"" } }";
var dict = JsonConvert.DeserializeObject<Dictionary<string, dynamic>>(json);
dynamic dyn = dict["blah"];
Console.WriteLine(dyn.GetType().FullName); // Newtonsoft.Json.Linq.JObject
Console.WriteLine(dyn["2"].ToString()); // foo
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如果你想Dictionary<string, string>改为,你可以像这样转换它:
Dictionary<string, string> newDict =
((IEnumerable<KeyValuePair<string, JToken>>)dyn)
.ToDictionary(kvp => kvp.Key, kvp => kvp.Value.ToString());
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ema*_*ema 21
您可以使用反射填充字典:
public Dictionary<String, Object> Dyn2Dict(dynamic dynObj)
{
var dictionary = new Dictionary<string, object>();
foreach (PropertyDescriptor propertyDescriptor in TypeDescriptor.GetProperties(dynObj))
{
object obj = propertyDescriptor.GetValue(dynObj);
dictionary.Add(propertyDescriptor.Name, obj);
}
return dictionary;
}
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您可以使用Json.Net将其反序列化为字典.
string json = dynamicObject.ToString(); // suppose `dynamicObject` is your input
Dictionary<string, string> dictionary = JsonConvert.DeserializeObject<Dictionary<string, string>>(json);
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