use*_*558 10 sql postgresql pivot crosstab
我有以下数据:
ID CLASS VALUE
1 NHB 700905.7243
1 HBW 164216.1311
1 HBO 700905.7243
2 NHB 146023.3792
2 HBW 89543.2972
2 HBO 82152.072
3 NHB 1409818.328
3 HBW 220430.7922
3 HBO 323512.9391
4 NHB 48711.3814
4 HBW 163385.1575
4 HBO 363352.3441
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我想重组为:
ID HBO HBW NHB
1 700905.7243 164216.1311 700905.7243
2 82152.072 89543.2972 146023.3792
3 323512.9391 220430.7922 1409818.328
4 363352.3441 163385.1575 48711.3814
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请注意,HBW,HBO和NHB列中的值是总计(总和).
这是我用来创建输出的脚本:
-- CREATE EXTENSION tablefunc;
SELECT *
FROM CROSSTAB
(
'SELECT _tlfd.id,
_tlfd."class",
_tlfd."value"
FROM public._tlfd
WHERE _tlfd."class" = ''HBW'' or _tlfd."class" = ''HBO'' or _tlfd."class" = ''NHB''
ORDER BY 1,2'
)
AS
(
"class" int,
"HBW" text,
"HBO" text,
"NHB" text,
--"Purpose" varchar,
"value" double precision
);
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当我运行脚本时,我收到此错误:
Run Code Online (Sandbox Code Playgroud)ERROR: return and sql tuple descriptions are incompatible.
我不确定这意味着什么以及如何纠正错误.有人可以告诉我:
Erw*_*ter 11
这对Postgres 9.3有用:
SELECT *
FROM crosstab (
$$SELECT id, class, "value"
FROM _tlfd
WHERE class = ANY ('{HBW, HBO, NHB}')
ORDER BY 1,2$$
)
AS
t ( class int, -- needs a table alias!
"HBW" float8, -- resulting columns are double precision!
"HBO" float8,
"NHB" float8
-- "value" double precision -- column does not exist in result!
);Run Code Online (Sandbox Code Playgroud)
产生所需的输出.我无法提供SQLfiddle,因为无法在那里安装其他模块.
t)"value"double precision又名float8)其余的是品味和风格.我不会value用作列名,因为它是SQL中的保留字.
这个相关答案的细节:
PostgreSQL交叉表查询