Ami*_*rad 1 sql postgresql date
我有以下查询
select substring(listDate from '............$') as v_end_date,
substring(listDate from '^...............') as v_start_date
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现在 listDate 值可以是这样的
select substring('06 Jan 2014 to 12 Jan 2014,
13 Jan 2014 to 19 Jan 2014,
20 Jan 2014 to 26 Jan 2014
' from '............$') as v_end_date,
substring('06 Jan 2014 to 12 Jan 2014,
13 Jan 2014 to 19 Jan 2014,
20 Jan 2014 to 26 Jan 2014
' from '^............') as v_start_date
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以上查询结果为
V_END_DATE V_START_DATE
26 Jan 2014 06 Jan 2014
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现在我需要有v_end_date
和v_start_date
格式 likeyyyy-mm-dd
和 like
Mon 06 Jan 2014
。
将您的字符串转换为实际的字符串date
并to_date()
使用它to_char()
来获得几乎任何您喜欢的格式。
演示:
SELECT to_char(day, 'YYYY-MM-DD') AS format1
, to_char(day, 'Dy DD Mon YYYY') AS format2
FROM (SELECT to_date('26 Jan 2014', 'DD Mon YYYY') AS day) sub
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