Python:在 xml.etree 元素上指定 XMLNS

csp*_*rpa 4 python schema elementtree xml-namespaces

在我的 Python 代码中,我当前正在使用该xml.etree库创建一棵树,然后将其转储到 XML 字符串。不幸的是,我无法使用 Python 标准库中的模块以外的模块来执行此操作。

这是我的代码:

import xml.etree.ElementTree as ET

def dump_to_XML():
  root_node = ET.Element("root")
  c1_node = ET.SubElement(root_node, "child1")
  c1_node.text = "foo"
  c2_node = ET.SubElement(root_node, "child2")
  gc1_node = ET.SubElement(c2_node, "grandchild1")
  gc1_node.text = "bar"
  return ET.tostring(root_node, encoding='utf8', method='xml')
Run Code Online (Sandbox Code Playgroud)

给出字符串:

<?xml version='1.0' encoding='utf8'?>
<root>
    <child1>foo</child1>
    <child2>
        <grandchild1>bar</grandchild1>
    </child2>
</root>
Run Code Online (Sandbox Code Playgroud)

现在,我有两个架构文件 - 比如说 -http://myhost.com/p.xsdhttp://myhost.com/q.xsd,我希望将输出字符串转换为:

<?xml version='1.0' encoding='UTF-8'?>
<root xmlns:p="http://myhost.com/p.xsd" xmlns:q="http://myhost.com/q.xsd">
    <p:child1>foo</p:child1>
    <p:child2>
        <q:grandchild1>bar</q:grandchild1>
    </p:child2>
</root>
Run Code Online (Sandbox Code Playgroud)

我如何利用etree图书馆来实现这一目标?

提前致谢

csp*_*rpa 5

开始了:

import xml.etree.ElementTree as ET

xmlns_uris = {'p': 'http://myhost.com/p.xsd',
              'q': 'http://myhost.com/q.xsd'}

def dump_to_XML():
  root_node = ET.Element("root")
  c1_node = ET.SubElement(root_node, "child1")
  c1_node.text = "foo"
  c2_node = ET.SubElement(root_node, "child2")
  gc1_node = ET.SubElement(c2_node, "grandchild1")
  gc1_node.text = "bar"
  annotate_with_XMLNS_prefixes(gc1_node, 'q', False)
  annotate_with_XMLNS_prefixes(root_node, 'p')
  add_XMLNS_attributes(root_node, xmlns_uris)
  return ET.tostring(root_node, encoding='UTF-8', method='xml')

def annotate_with_XMLNS_prefixes(tree, xmlns_prefix, skip_root_node=True):
    if not ET.iselement(tree):
        tree = tree.getroot()
    iterator = tree.iter()
    if skip_root_node: # Add XMLNS prefix also to the root node?
        iterator.next()
    for e in iterator:
        if not ':' in e.tag:
            e.tag = xmlns_prefix + ":" + e.tag

def add_XMLNS_attributes(tree, xmlns_uris_dict):
    if not ET.iselement(tree):
        tree = tree.getroot()
    for prefix, uri in xmlns_uris_dict.items():
        tree.attrib['xmlns:' + prefix] = uri
Run Code Online (Sandbox Code Playgroud)

执行:print dump_to_XML()给出:

<?xml version='1.0' encoding='UTF-8'?>
<root xmlns:p="http://myhost.com/p.xsd" xmlns:q="http://myhost.com/q.xsd">
    <p:child1>foo</p:child1>
    <p:child2>
        <q:grandchild1>bar</q:grandchild1>
    </p:child2>
</root>
Run Code Online (Sandbox Code Playgroud)