WoJ*_*oJo 6 javascript performance html5 google-maps deferred
我正在努力确保Google地图是在页面上加载的最后一件事,并且不会对页面的性能产生负面影响.
当defer属性放在...... sensor = false之后时,地图不会出现.使用Google地图的defer属性的最佳方法是什么?这是否可能?
<div id="map-canvas"></div>
<script src="http://maps.googleapis.com/maps/api/js?key=AIzaSyDY0kkJiTPVd2U7aTOAwhc9ySH6oHxOIYM&sensor=false" defer></script>
<script defer>
function initialize() {
var mapOptions = {
center: new google.maps.LatLng(37.7599446, -122.4212681),
zoom: 12,
panControl: false,
disableDefaultUI: true,
scrollwheel: false,
mapTypeControl: false,
mapTypeControlOptions: {
style: google.maps.MapTypeControlStyle.HORIZONTAL_BAR
},
panControlOptions: {
position: google.maps.ControlPosition.LEFT_CENTER
},
zoomControl: true,
zoomControlOptions: {
position: google.maps.ControlPosition.LEFT_CENTER
},
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById("map-canvas"),
mapOptions);
var marker = new google.maps.Marker({
position: new google.maps.LatLng(37.7599446, -122.4212681),
map: map,
title: '805 Valencia St. San Francisco, CA'
});
var contentString = '<div id="map-content">' +
'<div id="siteNotice">' +
'</div>' +
'<h1 id="firstHeading" class="firstHeading">805 Valencia St.<br>San Francisco, CA</h1>' +
'<div id="bodyContent">' +
'' +
'<ul class="email-list"><li>info@yourbetty.com</li><li>support@yourbetty.com</li><li>press@yourbetty.com</li></ul>' +
'</div>' +
'</div>';
var infowindow = new google.maps.InfoWindow({
content: contentString,
maxWidth: 330
});
google.maps.event.addListener(marker, 'click', function () {
infowindow.open(map, marker);
});
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>
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Dr.*_*lle 10
使用延迟时,必须使用API的异步版本:
<script defer
src="http://maps.googleapis.com/maps/api/js?sensor=false&callback=initialize">
</script>
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问题:
当您使用defer
脚本时,将在文档关闭时加载 - 内容已加载.此外,在内联defferred脚本之后将解析外部自定义脚本.
这有两个与您的实现相关的副作用:
您不能使用API的同步版本,因为它使用了document.write
,在文档关闭后无法使用
电话:
google.maps.event.addDomListener(window, 'load', initialize);
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......还没有加载Maps-API,google
未定义,初始化永远不会被执行.