编译错误:函数不带1个参数

Question

void displayCost();
double computeArea();
double roundCost();

int main()
{
    return 0;
}

void displayCost(string name, int size)
{
    double area = computeArea(size);

    cout << "Since a " << size << "-inch pizza covers" << area << "square inches, "
         << name << ", then a 12 cents per square inch, the cost will be" << 12*area
         << " - which rounds to" << roundCost();
}

double computeArea(int size)
{
    double radius = size/2;
    double area = pi*radius*radius;
    return area;
}

double roundCost(double price)
{
    double roundedCost = ceil(price*100)/100;
    return roundedCost;
}

它发生在线上double area = computeArea(size);.我不明白为什么它说我没有在我清楚的时候通过论证.

Answer 1

double computeArea();
double area = computeArea(size);
double computeArea(int size) {

这些事情之一是不喜欢别人...

您需要修复原型(第一个)以匹配实际功能:

double computeArea(int);

当然,同样适用于其他原型.